Is there a way in .Net to get a string value for an int's word?
For example:
(1).SomeFunction().Equals("one")
(2).SomeFunction().Equals("two")
I really only need it for digits 1-9 in the case I'm working with, should I just use a switch/select case?
Update I won't need localization in this case either.
Update 2 Here's what I ended up using:
Private Enum EnglishDigit As Integer
zero
one
two
three
four
five
s开发者_高级运维ix
seven
eight
nine
End Enum
(CType(someIntThatIsLessThanTen, EnglishDigit)).ToString()
How about an enumeration?
enum Number
{
One = 1, // default value for first enum element is 0, so we set = 1 here
Two,
Three,
Four,
Five,
Six,
Seven,
Eight,
Nine,
}
Then you can type things like...
((Number)1).ToString()
If you need localization then you can add a DescriptionAttribute
to each enum value. The attribute's Description
property would store the name of the resourse item's key.
enum Number
{
[Description("NumberName_1")]
One = 1, // default value for first enum element is 0, so we set = 1 here
[Description("NumberName_2")]
Two,
// and so on...
}
The following function will grab the value of the Description
property from the attribute
public static string GetDescription(object value)
{
DescriptionAttribute[] attributes = null;
System.Reflection.FieldInfo fi = value.GetType().GetField(value.ToString());
if (fi != null)
{
attributes = (DescriptionAttribute[])fi.GetCustomAttributes(typeof(DescriptionAttribute), false);
}
string description = null;
if ((attributes != null) && (attributes.Length > 0))
{
description = attributes[0].Description;
}
return description;
}
This can be called in the following manner:
GetDescription(((Number)1))
From that you can then pull the relevant value from the resource file, or just call .ToString()
if null
was returned.
Edit
Various commenters have pointed out (and I have to agree) that it would be simpler to just use the enum value names to reference localised strings.
create a dictionary of strings:
string[] digits = new string[]
{
"zero",
"one",
"two",
...
};
string word = digits[digit];
Use a lookup table; an array will do. It's no slower than an enum, and it's easier to localize.
edit
Andrey's code sample is what I was suggesting, although I think calling it a dictionary is a bit confusing.
If you don't need localization, I'd suggest Richard Ev's solution. For localization, however, I'd suggest adding the ten digit names to a resource file, for example NumberName_0
to NumberName_9
. This way, when looking up a number, you can just load the resource with the name String.Format("NumberName_{0}", mydigit)
.
The same technique, by the way, also works fine for localizable enumeration names or descriptions.
Why stop at 1-9...
C#'s version of the way Squeak Smalltalk does it for all numbers to a vigintillion:
public static String AsWords(this int aNumber) {
var answer = "";
if (aNumber == 0) return "zero";
if (aNumber < 0) {
answer = "negative";
aNumber = Math.Abs(aNumber);
}
var thousands = new[] {"", "thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion", "septillion","octillion", "nonillion", "decillion", "undecillion", "duodecillion", "tredecillion", "quattuordecillion", "quindecillion", "sexdecillion", "septendecillion", "octodecillion", "novemdecillion", "vigintillion"};
var thousandCount = 0;
while (aNumber > 0) {
var underOneThousandName = ThreeDigitName(aNumber % 1000);
aNumber = aNumber / 1000;
if(underOneThousandName != "") {
if (answer != "") answer = "," + answer;
answer = underOneThousandName + " " + thousands[thousandCount] + answer;
}
thousandCount += 1;
}
return answer;
}
private static string ThreeDigitName(int aNumberLessThanOneThousand) {
if (aNumberLessThanOneThousand == 0) return "";
var units = new[] {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eightteen", "nineteen"};
var answer = "";
if (aNumberLessThanOneThousand > 99) {
answer = units[(aNumberLessThanOneThousand / 100) - 1] + " hundred";
if (aNumberLessThanOneThousand % 100 != 0)
answer += " " + ThreeDigitName(aNumberLessThanOneThousand % 100);
return answer;
}
if (aNumberLessThanOneThousand < 20) return units[aNumberLessThanOneThousand -1];
var multiplesOfTen = new[] {"twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"};
answer += multiplesOfTen[(aNumberLessThanOneThousand / 10)-2];
if (aNumberLessThanOneThousand % 10 != 0) answer += "-" + units[(aNumberLessThanOneThousand % 10)-1];
return answer;
}
I don't think there are any built-in functions to do this. I would use select case.
If you are using 2008:
public static String AsWord(this int aNumber) {
return ((Number) aNumber).ToString();
}
enum Number {
One = 1,
Two,
Three,
Four,
Five,
Six,
Seven,
Eight,
Nine,
}
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