MYSQL query to return rows that are NOT in a set

I have two tables:

Contact (id,name) Link开发者_如何转开发 (id, contact_id, source_id)

I have the following query which works that returns the contacts with the source_id of 8 in the Link table.

SELECT name FROM `Contact` LEFT JOIN Link ON Link.contact_id = Contact.id WHERE Link.source_id=8;

However I am a little stumped on how to return a list of all the contacts which are NOT associated with source_id of 8. A simple != will not work as contacts without any links are not returned.

Thanks.

Just say WHERE Link.source_id != 8;

Use:

   SELECT c.name 
     FROM CONTACT c
LEFT JOIN LINK l ON l.contact_id = c.id
                AND l.source_id = 8
    WHERE l.contact_id IS NULL

There's a straight-forwarrd way to do it just as you expressed it.

SELECT name FROM .... WHERE Link.source_id != 8;

You can change the where condition from:

Link.source_id = 8;

to

Link.source_id != 8;

You can also use <> in place of !=

Both are the not equal operator in MySQL

Shouldnt this work?

WHERE Link.source_id <> 8 OR Link.source_id IS NULL