Scala create List[Int]
How can I quickly create a List[开发者_如何学GoInt]
that has 1 to 100 in it?
I tried List(0 to 100)
, but it returns List[Range.Inclusive]
Thanks
Try
(0 to 100).toList
The code you tried is creating a list with a single element - the range. You might also be able to do
List(0 to 100:_*)
Edit
The List(...)
call takes a variable number of parameters (xs: A*
). Unlike varargs in Java, even if you pass a Seq
as a parameter (a Range
is a Seq
), it will still treat it as the first element in the varargs parameter. The :_*
says "treat this parameter as the entire varargs Seq
, not just the first element".
If you read : A*
as "an (:
) 'A' (A
) repeated (*
)", you can think of :_*
as "as (:
) 'something' (_
) repeated (*
)"
List.range(1,101)
The second argument is exclusive so this produces a list from 1 to 100.
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