Convert a dataframe to a vector (by rows)
I h开发者_C百科ave a dataframe with numeric entries like this one
test <- data.frame(x = c(26, 21, 20), y = c(34, 29, 28))
How can I get the following vector?
> 26, 34, 21, 29, 20, 28
I was able to get it using the following, but I guess there should be a much more elegant way
X <- test[1, ]
for (i in 2:dim(test)[ 1 ]){
X <- cbind(X, test[i, ])
}
You can try as.vector(t(test))
. Please note that, if you want to do it by columns you should use unlist(test)
.
c(df$x, df$y)
# returns: 26 21 20 34 29 28
if the particular order is important then:
M = as.matrix(df)
c(m[1,], c[2,], c[3,])
# returns 26 34 21 29 20 28
Or more generally:
m = as.matrix(df)
q = c()
for (i in seq(1:nrow(m))){
q = c(q, m[i,])
}
# returns 26 34 21 29 20 28
You can try this to get your combination:
as.numeric(rbind(test$x, test$y))
which will return:
26, 34, 21, 29, 20, 28
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