Regular expression for checking website url
I need to check the web address, using regular expression.
if user type url as
- www.test.com
- http://www.test.c开发者_运维技巧om
- https://www.test.com
i have a regular expression like
/^(http\:\/\/[a-zA-Z0-9_\-]+(?:\.[a-zA-Z0-9_\-]+)*\.[a-zA-Z]{2,4}(?:\/[a-zA-Z0-9_]+)*(?:\/[a-zA-Z0-9_]+\.[a-zA-Z]{2,4}(?:\?[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)?)?(?:\&[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)*)$/
but it will only allow the second option only. how can i modify the regular expression so that , it should accept 1st and 3rd option too
This is a pretty basic expression for testing domain names:
@^(http\:\/\/|https\:\/\/)?([a-z0-9][a-z0-9\-]*\.)+[a-z0-9][a-z0-9\-]*$@i
Should match:
domain.com
www.domain.com
http://domain.com
https://domain.com
Use the following program for validating the website URL.
It will be validating the following and any valid website URL.
- www.test.com
- http://www.test.com
- https://www.test.com
<?php
$string_url="https://www.test.com";
$reg_exp = "/^(http(s?):\/\/)?(www\.)+[a-zA-Z0-9\.\-\_]+(\.[a-zA-Z]{2,3})+(\/[a-zA-Z0-9\_\-\s\.\/\?\%\#\&\=]*)?$/";
if(preg_match($reg_exp, $string_url) == TRUE){
echo "URL is valid format";
}
else{
echo "URL is invalid format";
}
?>
You can use this pattern also:
(http(s)?://)?([\w-]+\.)+[\w-]+(/[\w- ;,./?%&=]*)?
This will work for matching:
http://www.google.com
https://www.google.com
www.google.com
google.com
google.in
Simple pattern for matching.
Hope this will help someone!!!
You can make the http://
optional and also the s
in https
optional as:
/^((?:http(?:s)?\:\/\/)?[a-zA-Z0-9_-]+(?:.[a-zA-Z0-9_-]+)*.[a-zA-Z]{2,4}(?:\/[a-zA-Z0-9_]+)*(?:\/[a-zA-Z0-9_]+.[a-zA-Z]{2,4}(?:\?[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)?)?(?:\&[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)*)$/
Pattern
(https?:\/\/)?([\w\d]+\.)?[\w\d]+\.\w+\/?.+
This will work for matching:
www.demo.com
http://foo.co.uk/
Try the following instead :
filter_var($your_variable, FILTER_VALIDATE_URL);
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