How can I match everything in a string until the second occurrence of a delimiter with a regular expression?

I am trying to refine a preg_match_all by finding the second occurrence of a period then a space:

<?php

$str = "East Winds 20开发者_如何学运维 knots. Gusts to 25 knots. Waters a moderate chop.  Slight chance of showers.";

preg_match_all ('/(^)((.|\n)+?)(\.\s{2})/',$str, $matches);

$dataarray=$matches[2];
foreach ($dataarray as $value)
{ echo $value; }
?>

But it does not work: the {2} occurrence is incorrect.

I have to use preg_match_all because I am scraping dynamic HTML.

I want to capture this from the string:

East Winds 20 knots. Gusts to 25 knots.

Here is a different approach

$str = "East Winds 20 knots. Gusts to 25 knots. Waters a moderate chop.  Slight chance of showers.";


$sentences = preg_split('/\.\s/', $str);

$firstTwoSentences = $sentences[0] . '. ' . $sentences[1] . '.';


echo $firstTwoSentences; // East Winds 20 knots. Gusts to 25 knots.

Why not just get all periods then a space and only use some of the results?

preg_match_all('!\. !', $str, $matches);
echo $matches[0][1]; // second match

I'm not sure what exactly you want to capture from this however. Your question is a little vague.

Now if you want to capture everything up to and including the second period (followed by a space) try:

preg_match_all('!^((?:.*?\. ){2})!s', $str, $matches);

It uses a non-greedy wildcard match and DOTALL so . matches newlines.

If you don't want to capture the last space, you can do that too:

preg_match_all('!^((?:.*?\.(?= )){2})!s', $str, $matches);

Also you may want to allow the string termination to count, which means either:

preg_match_all('!^((?:.*?\.(?: |\z)){2})!s', $str, $matches);

or

preg_match_all('!^((?:.*?\.(?= |\z)){2})!s', $str, $matches);

Lastly, since you're after one match and want the first one, you could just as easily use preg_match() rather than preg_match_all() for this.

I don't think (.\s{2}) means what you think it means. As it stands, it will match ". " (a period followed by two spaces), not the second occurence of ". "

You can try:

<?php
$str = "East Winds 20 knots. Gusts to 25 knots. Waters a moderate chop.  Slight chance of showers.";
if(preg_match_all ('/(.*?\. .*?\. )/',$str, $matches))
    $dataarrray = $matches[1];
var_dump($dataarrray);
?>

Output:

array(1) {
  [0]=>
  string(40) "East Winds 20 knots. Gusts to 25 knots. "
}

Also if you want to capture just one occurrence, why are you using preg_match_all ? preg_match should suffice.

no need regex. think simple

$str = "East Winds 20 knots. Gusts to 25 knots. Waters a moderate chop.  Slight chance of showers.";
$s = explode(". ",$str);
$s = implode(". ",array_slice($s,0,2)) ;
print_r($s);

I want to capture this from the string: East Winds 20 knots. Gusts to 25 knots.

I have two suggestions:

1) Simply Explode the string at ". " (double space) and just print the result.

$arr = explode(".  ",$str);
echo $arr[0] . ".";
// Output: East Winds 20 knots. Gusts to 25 knots.

2) Use Explode and Strpos which is more performance-friendly than Preg_match_all.

foreach( explode(".",$str) as $key=>$val) {
    echo (strpos($val,"knots")>0) ? trim($val) . ". " : "";
}
// Output: East Winds 20 knots. Gusts to 25 knots.