Function returns CSV File: How to go about checking it?
I am doing something like:
$outputFile = getCurrentDBSnapshot($data);
where $data is the resource stream that am passing in, basically from command prompt am passing an file and am opening it using fopen for writing with 'w+' permissions, now getCurrentDBSnapshot would get the current state of a table and would update the $data csv file, so basically $outputFile would be updated with the current state of database table, now I want to var_dump or print the value of $outputFile to see the data present into it.
But when I do
$this->开发者_如何学Pythonfout = fopen($outputFile,'r') or die('Cannot open file');
$test = fgetcsv($outputFile,5000,";");
var_dump($test);
It gives me an error saying that it expects parameter 1 to be a string type and am passing resource.
My goal to see the contains of $outputFile
and so my question is that
How can I see the contains present in $outputFile or how can I see what getcurrentDBSnapshot function is returning me ?
fegtcsv
takes as first parameter a file handle, not a filename. You'll need to do something like:
$this->fout = fopen($outputFile,'r') or die('Cannot open file');
while ($test = fgetcsv($this->fout,5000,";"))
{
var_dump($test);
}
Note that fgetcsv
merely gets a single line of the file, analogously to fgets.
Also I'm not sure why you're passing a semicolon as the third argument to fgetcsv
. CSV stands for comma-separated-value; are you sure your file is semicolon-delimited?
Quoting the fgetcsv
page of the manual, the first parameter passed to fgetcsv
should be :
A valid file pointer to a file successfully opened by
fopen()
,popen()
, orfsockopen()
.
Here, you are passing as first parameter $outputFile
, which contains the name of the file you are trying to read from -- i.e. a string, and not a handle to an opened file.
Considering you are calling fopen
and storing its return-value in $this->fout
, this is probably the variable you should be passing to fgetcsv
, like this :
$this->fout = fopen($outputFile,'r') or die('Cannot open file');
$test = fgetcsv($this->fout,5000,";");
var_dump($test);
As a sidenote : fgetcsv
will only return the data of one line each time you call it -- which means you might have to use a loop, if you want to see the content of the whole file.
If needed, take a look at Example #1, on the manual page of fgetcsv
.
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