SQL group by: using where-clause logic to filter results based on aggregate functions
I h开发者_如何转开发ave a basic group by/avg statement:
select url, avg(contentping+tcpping), count(*) from websites ws, ping pi
where ws.idwebsite = pi.idwebsite and errortype is null
group by url order by avg(contentping+tcpping) asc;
What I want to do now is to drop any results which have a higher than average ping of 500. How can I do this...?
just add a having
clause:
select url, avg(contentping+tcpping), count(*) from websites ws, ping pi
where ws.idwebsite = pi.idwebsite and errortype is null
group by url
having avg(contenetping+tcpping) < 500
order by avg(contentping+tcpping) asc;
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