How do I add a default namespace with no prefix using XMLSerializer
I am trying to generate an XML document that contains the default namespace without a prefix using XmlSerializer
, e.g.
<?xml version="1.0" encoding="utf-8" ?>
<MyRecord ID="9266" xmlns="http://www.website.com/MyRecord">
<List>
<SpecificItem>
Using the following code ...
string xmlizedString = null;
MemoryStream memoryStream = new MemoryStream();
XmlSerializer xs = new XmlSerializer(typeof(ExportMyRecord));
XmlSerializerNamespaces xmlnsEmpty = new XmlSerializerNamespaces();
xmlnsEmpty.Add(string.Empty, string.Empty);
XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
xs.Serialize(xmlTextWriter, myRecord, xmlnsEmpty);
memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
xmlizedString = this.UTF8ByteArrayToString(memoryStream.ToArray());
and class structure ...
[Serializable]
[XmlRoot(开发者_运维技巧"MyRecord")]
public class ExportMyRecord
{
[XmlAttribute("ID")]
public int ID { get; set; }
Now, I've tried various options ...
XmlSerializer xs = new XmlSerializer
(typeof(ExportMyRecord),"http://www.website.com/MyRecord");
or ...
[XmlRoot(Namespace = "http://www.website.com/MyRecord", ElementName="MyRecord")]
gives me ...
<?xml version="1.0" encoding="utf-8"?>
<q1:MylRecord ID="9266" xmlns:q1="http://www.website.com/MyRecord">
<q1:List>
<q1:SpecificItem>
I need the XML to have the namespace without the prefix as it's going to a third party provider and they reject all other alternatives.
There you go:
ExportMyRecord instance = GetInstanceToSerializeFromSomewhere();
XmlSerializerNamespaces xmlnsEmpty = new XmlSerializerNamespaces();
xmlnsEmpty.Add(string.Empty, "http://www.website.com/MyRecord");
var serializer = new XmlSerializer(
instance.GetType(),
"http://www.website.com/MyRecord"
);
Here's a generic implementation that can be used for any type:
public static void Serialize<T>(T instance, string defaultNamespace, Stream stream)
{
var namespaces = new XmlSerializerNamespaces();
namespaces.Add(string.Empty, defaultNamespace);
var serializer = new XmlSerializer(typeof(T), defaultNamespace);
serializer.Serialize(stream, instance, namespaces);
}
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