Problem with jQuery array
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js" type="text/javascript"></script>
<script type="text/jscript">
$('document').ready(function (){
var clickNo=0;
$('div#pics>img').hide()
$('div#pics>input').click(function(event){
$('div#pics>img')[0].show('slow');
})
});
</script>
</head>
<body>
<div id="pics">
<input type="button" value="next" />
<--a bunch of img tags .I had to resort to this comment bec开发者_运维技巧ause the system won't
let me include the img tag in the code-->
</div>
</body>
</html>
I can't understand why the line $('div#pics>img')[0].show('slow'); is not working.
This gets the native DOM element, not the jQuery object (which doesn't have a .show() function), what you want instead is :first like this so you get the jQuery object:
$('div#pics>img:first').show('slow');
Or, in your current format, get the first match like this:
$('div#pics>img:eq(0)').show('slow');
//Or..
$('div#pics>img').eq(0).show('slow');
I assume that number will change/climb, so the last option seems like the best approach in your case.
I have several pieces of advice:
If the images are meant to be hidden on page load, hide them with CSS not Javascript;
There is little value in specifying a tag name and an ID (
div@pics). Just specify the ID (#pics);The array notation (
[0]) is shorthand forget(0). It returns a DOM element and not a jQuery object. The jQuery object is the one that has ashow()method; andjQuery is up to 1.4.2; and
I'm not sure exactly what you're trying to do with your
click()handler. The name "next" implies you want to cycle through them?
Incorporating all that:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<style type="text/css">
#pics img { display: none; }
</style>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" type="text/javascript"></script>
<script type="text/jscript">
$(function() {
$("#pics > input").click(function(event) {
var images = $("#pics img");
var visible = images.filter(":visible");
if (visible.length == 0) {
images.eq(0).show("slow");
} else {
var index = images.index(visible[0]);
visible.hide("slow");
$(images[(index + 1) % images.length]).show("slow");
}
});
});
</script>
</head>
<body>
<div id="pics">
<input type="button" value="next" />
<--a bunch of img tags .I had to resort to this comment because the system won't
let me include the img tag in the code-->
</div>
</body>
</html>
加载中,请稍侯......
精彩评论