mysql query: SELECT DISTINCT column1, GROUP BY column2
Right now I have the following query:
SELECT name, COUNT(name), time, price, ip, SUM(price)
FROM tablename
WHERE time >= $yesterday
AND time <$today GROUP BY name
And what I'd like to do is add a DISTINCT by column 'ip', i.e.
SELECT开发者_StackOverflow DISTINCT ip FROM tablename
So my final output would be all the columns, from all the rows that where time is today, grouped by name (with name count for each repeating name) and no duplicate ip addresses.
What should my query look like? (or alternatively, how can I add the missing filter to the output with php)?
Thanks in advance.
[UPDATE]
To minimize confusion, consider this (simplified) db table:
| name | ip |
---------------------
| mark | 123 |
| mark | 123 |
| mark | 456 |
| dave | 789 |
| dave | 087 |
The result I'm looking for would be an HTML table looking like this:
| name | name count |
----------------------------
| mark | 2 |
| dave | 2 |
What I'm currently getting is:
| name | name count |
----------------------------
| mark | 3 |
| dave | 2 |
(it counts mark 3 times, even though two times are with the same ip).
You can use COUNT(DISTINCT ip)
, this will only count distinct values, for instance:
SELECT name, COUNT(name), time, price, COUNT(DISTINCT ip), SUM(price)
FROM tablename
WHERE time >= :yesterday
AND time < :today GROUP BY name
Replacing FROM tablename
with FROM (SELECT DISTINCT * FROM tablename)
should give you the result you want (ignoring duplicated rows) for example:
SELECT name, COUNT(*)
FROM (SELECT DISTINCT * FROM Table1) AS T1
GROUP BY name
Result for your test data:
dave 2
mark 2
You can just add the DISTINCT(ip)
, but it has to come at the start of the query. Be sure to escape PHP variables that go into the SQL string.
SELECT DISTINCT(ip), name, COUNT(name) nameCnt,
time, price, SUM(price) priceSum
FROM tablename
WHERE time >= $yesterday AND time <$today
GROUP BY ip, name
Somehow your requirement sounds a bit contradictory ..
group by name (which is basically a distinct on name plus readiness to aggregate) and then a distinct on IP
What do you think should happen if two people (names) worked from the same IP within the time period specified?
Did you try this?
SELECT name, COUNT(name), time, price, ip, SUM(price)
FROM tablename
WHERE time >= $yesterday AND time <$today
GROUP BY name,ip
Try the following:
SELECT DISTINCT(ip), name, COUNT(name) nameCnt,
time, price, SUM(price) priceSum
FROM tablename
WHERE time >= $yesterday AND time <$today
GROUP BY ip, name
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