What is the smallest, legal zip/jar file?
I hate generating an exception for things that I can simply test with an if statement. I know that a zero length zip/开发者_开发技巧jar will trigger an exception if you try to access it using the java.util.zip/java.util.jar APIs. So, it seems like there should be a smallest file that these utility APIs are capable of working with.
You really should put this sort of code into a try/catch as there are many things that can go wrong when reading/writing files?
If you really must know the answer to this then try to add a 1 byte file to a zip and then see if that fails? It's easy code to go through a range of sizes from 1 -> 65536 bytes and add to a zip and see which ones fail?
According to ZIP file format specs a zip file should at least have the central directory structure that is 46 bytes long + 3 variable fields (check the spec by yourself).
Maybe we should assume at least 1 entry that implies the file header for that entry.
Jar files need to have at least one entry. If you want to make an empty one make a manifest only jar.
See JAR Manifest for more info on jar manifests.
I wrote a quick test and the smallest zip that I could create and then read back with the java.util.zip APIs was 118 byte. There may be a way to create a smaller zip file that is spec compliant and readable with the zip utility...
The smallest legal zip contains zero entries, and one "empty" central directory.
The bytes are:
80 75 05 06
followed by 18 bytes of zero (0).
So, 22 bytes long.
VBscript to create it:
Sub NewZip(pathToZipFile)
WScript.Echo "Newing up a zip file (" & pathToZipFile & ") "
Dim fso
Set fso = CreateObject("Scripting.FileSystemObject")
Dim file
Set file = fso.CreateTextFile(pathToZipFile)
file.Write Chr(80) & Chr(75) & Chr(5) & Chr(6) & String(18, 0)
file.Close
Set fso = Nothing
Set file = Nothing
WScript.Sleep 500
End Sub
NewZip "Empty.zip"
final static byte[] EmptyZip={80,75,05,06,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00};
public static void createEmptyZip(String path){
try{
FileOutputStream fos=new FileOutputStream(new File(path));
fos.write(EmptyZip, 0, 22);
fos.flush();
fos.close();
}catch (FileNotFoundException e){
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
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