C, Dealing with variable argument functions
L开发者_开发技巧et's say I want to do something like this
void my_printf(char *fmt,...) {
char buf[big enough];
sprintf(buf,fmt,...);
}
What is the proper way of passing the variable number of arguments directly to a function with accepts variable arguments?
sprintf
has a va_list
form called vsprintf
. Pass the va_list
you construct locally to it as the last argument.
void my_printf(char *fmt,...) {
va_list ap;
va_start(ap, fmt);
char buf[big enough];
vsprintf(buf,fmt,ap);
va_end(ap);
}
I'm not sure how useful this code will be, as it is C++, but it shows how to check, using a Win32 specific function vsnprintf(), that the buffer allocated is big enough and if not allocates a bigger one. And it returns a std::string, so you would have to use malloc/realloc to handle that. But what the hell:
string Format( const char * fmt, ... ) {
const int BUFSIZE = 1024;
int size = BUFSIZE, rv = -1;
vector <char> buf( size );
do {
va_list valist;
va_start(valist, fmt );
// if vsnprintf() returns < 0, the buffer wasn't big enough
// so increase buffer size and try again
rv = _vsnprintf( &buf[0], size, fmt, valist );
va_end( valist );
size *= 2;
buf.resize( size );
}
while( rv < 0 );
return string( &buf[0] );
}
You can us the vsprintf style functions to get printf style printing for your variable length parameter. However there is no requrement to do so. You can if you choose write your function to keep accepting parameters until it encounters a null pointer.
va_list ap;
char *param;
va_start(ap,fmt);
param = va_arg(ap,char*);
while(param)
{
do something...
param = va_arg(ap,char*);
}
or you can have the number of parameters as the first param to your function
void my_printf(int param_num,...)
{
va_list ap;
char *param;
va_start(ap,fmt);
while(param_num)
{
do something...
param = va_arg(ap,char*);
param_num--;
}
}
Its really up to you, the possibilities are limitless. I think the only real requirement to the ellipses is that it has at least one parameter before the ellipses.
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