How can I get the source lines inline with the assembly output using GCC?
I'd like to get the C source lines inline with the assembly output to see what code is being generated.
I have tried GCC options like -S
-Wa,-开发者_如何学编程ahlms
(and even -Wa,--gstabs
'cause I read it somewhere).
Oh! BTW, I am on a Mac so I don't have objdump
.
(Sorry this is short, I have to get off the train!)
Output of gcc pc-clisp.c -S -g -fverbose-asm -fnested-functions
.globl _getBool
_getBool:
LFB32:
LM21:
pushl %ebp #
LCFI30:
movl %esp, %ebp #,
LCFI31:
subl $8, %esp #,
LCFI32:
LM22:
movzbl 8(%ebp), %eax # atom.pred, D.4112
movzbl %al, %eax # D.4112, D.4113
andl $-16, %eax #, D.4114
sarl $4, %eax #, D.4115
testl %eax, %eax # D.4115
setne %al #, tmp64
movzbl %al, %eax # tmp64, D.4111
leave
ret
LFE32:
Maybe debug + a post-process step?
gcc <source.c> -S -g -fverbose-asm
Find .file 1 "1.c"
to tell you the file number to file name mapping.
Then add source after the .loc 1 8 0
lines. I'm not sure how to do it with a single shell command, but a short script should be able to do it:
#!/usr/bin/env python
import re
import sys
filename = sys.argv[1]
f = open(filename)
lines = f.readlines()
f.close()
FILE_RE=re.compile(r"\s+\.file (\d+) \"(.*)\"")
LOC_RE =re.compile(r"\s+\.loc (\d+) (\d+)")
output = []
files = {}
for line in lines:
output.append(line)
mo = FILE_RE.match(line)
if mo is not None:
files[mo.group(1)] = open(mo.group(2)).readlines()
print mo.group(1),"=",mo.group(2)
continue
mo = LOC_RE.match(line)
if mo is not None:
print mo.group(1),"=",mo.group(2)
source = files[mo.group(1)][int(mo.group(2))-1]
output.append("\t#"+source)
f = open(filename+".2","w")
f.writelines(output)
f.close()
It's not exactly what you're asking for, but you may find -S -fverbose-asm
helpful.
you can get objdump via macports. just intall the "binutils" package and then use "gobjdump"
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