PHP json_decode() returns NULL with seemingly valid JSON?

I have this JSON object stored on a plain text file:

{
    "MySQL": {
        "Server": "(server)",
        "Username": "(user)",
        开发者_JAVA技巧"Password": "(pwd)",
        "DatabaseName": "(dbname)"
    },
    "Ftp": {
        "Server": "(server)",
        "Username": "(user)",
        "Password": "(pwd)",
        "RootFolder": "(rf)"
    },
    "BasePath": "../../bin/",
    "NotesAppPath": "notas",
    "SearchAppPath": "buscar",
    "BaseUrl": "http:\/\/montemaiztusitio.com.ar",
    "InitialExtensions": [
        "nem.mysqlhandler",
        "nem.string",
        "nem.colour",
        "nem.filesystem",
        "nem.rss",
        "nem.date",
        "nem.template",
        "nem.media",
        "nem.measuring",
        "nem.weather",
        "nem.currency"
    ],
    "MediaPath": "media",
    "MediaGalleriesTable": "journal_media_galleries",
    "MediaTable": "journal_media",
    "Journal": {
        "AllowedAdFileFormats": [
            "flv:1",
            "jpg:2",
            "gif:3",
            "png:4",
            "swf:5"
        ],
        "AdColumnId": "3",
        "RSSLinkFormat": "%DOMAIN%\/notas\/%YEAR%-%MONTH%-%DAY%\/%TITLE%/",
        "FrontendLayout": "Flat",
        "AdPath": "ad",
        "SiteTitle": "Monte Maíz: Tu Sitio",
        "GlobalSiteDescription": "Periódico local de Monte Maíz.",
        "MoreInfoAt": "Más información aquí, en el Periódico local de Monte Maíz.",
        "TemplatePath": "templates",
        "WeatherSource": "accuweather:SAM|AR|AR005|MONTE MAIZ",
        "WeatherMeasureType": "1",
        "CurrencySource": "cotizacion-monedas:Dolar|Euro|Real",
        "TimesSingular": "vez",
        "TimesPlural": "veces"
    }
}

When I try to decode it with json_decode(), it returns NULL. Why? The file is readable (I tried echoing file_get_contents() and it worked ok).

I've tested JSON against http://jsonlint.com/ and it's perfectly valid.

What's wrong here?

This worked for me

json_decode( preg_replace('/[\x00-\x1F\x80-\xFF]/', '', $json_string), true );

It could be the encoding of the special characters. You could ask json_last_error() to get definite information.

You could try with it.

json_decode(stripslashes($_POST['data']))

If you check the the request in chrome you will see that the JSON is text, so there has been blank code added to the JSON.

You can clear it by using

$k=preg_replace('/\s+/', '',$k);

Then you can use:

json_decode($k)

print_r will then show the array.

Maybe some hidden characters are messing with your json, try this:

$json = utf8_encode($yourString);
$data = json_decode($json);

I had the same problem and I solved it simply by replacing the quote character before decode.

$json = str_replace('"', '"', $json);
$object = json_decode($json);

My JSON value was generated by JSON.stringify function.

For me the php function stripslashes() works when receiving json from javascript. When receiving json from python, the second optional parameter to the json_decode call does the trick since the array is associative. Workes for me like a charm.

$json = stripslashes($json); //add this line if json from javascript
$edit = json_decode($json, true); //adding parameter true if json from python

this help you to understand what is the type of error

<?php
// A valid json string
$json[] = '{"Organization": "PHP Documentation Team"}';

// An invalid json string which will cause an syntax 
// error, in this case we used ' instead of " for quotation
$json[] = "{'Organization': 'PHP Documentation Team'}";


foreach ($json as $string) {
    echo 'Decoding: ' . $string;
    json_decode($string);

    switch (json_last_error()) {
        case JSON_ERROR_NONE:
            echo ' - No errors';
        break;
        case JSON_ERROR_DEPTH:
            echo ' - Maximum stack depth exceeded';
        break;
        case JSON_ERROR_STATE_MISMATCH:
            echo ' - Underflow or the modes mismatch';
        break;
        case JSON_ERROR_CTRL_CHAR:
            echo ' - Unexpected control character found';
        break;
        case JSON_ERROR_SYNTAX:
            echo ' - Syntax error, malformed JSON';
        break;
        case JSON_ERROR_UTF8:
            echo ' - Malformed UTF-8 characters, possibly incorrectly encoded';
        break;
        default:
            echo ' - Unknown error';
        break;
    }

    echo PHP_EOL;
}
?>

This error means that your JSON string is not valid JSON!

Enable throwing exceptions when an error happens and PHP will throw an exception with the reason for why it failed.

Use this:

$json = json_decode($string, null, 512, JSON_THROW_ON_ERROR);

Just thought I'd add this, as I ran into this issue today. If there is any string padding surrounding your JSON string, json_decode will return NULL.

If you're pulling the JSON from a source other than a PHP variable, it would be wise to "trim" it first:

$jsonData = trim($jsonData);

The most important thing to remember, when you get a NULL result from JSON data that is valid is to use the following command:

json_last_error_msg();

Ie.

var_dump(json_last_error_msg());
string(53) "Control character error, possibly incorrectly encoded"

You then fix that with:

$new_json = preg_replace('/[[:cntrl:]]/', '', $json);

Here is how I solved mine https://stackoverflow.com/questions/17219916/64923728 .. The JSON file has to be in UTF-8 Encoding, mine was in UTF-8 with BOM which was adding a weird &65279; to the json string output causing json_decode() to return null

In my case , i was facing the same issue , but it was caused by slashes inside the json string so using

json_decode(stripslashes($YourJsonString))

OR

json_decode( preg_replace('/[\x00-\x1F\x80-\xFF]/', '', $YourJsonString), true );

If the above doesnt work, first replace the quotes from html quote , this might be happening if you are sending data from javascript to php

    $YourJsonString = stripslashes($YourJsonString);
    $YourJsonString = str_replace('"', '"', $YourJsonString);
    $YourJsonString = str_replace('["', '[', $YourJsonString);
    $YourJsonString = str_replace('"]', ']', $YourJsonString);
    $YourJsonString = str_replace('"{', '{', $YourJsonString);
    $YourJsonString = str_replace('}"', '}', $YourJsonString);
    $YourJsonObject = json_decode($YourJsonString);

Will solve it,

If you are getting json from database, put

mysqli_set_charset($con, "utf8");

after defining connection link $con

Just save some one time. I spent 3 hours to find out that it was just html encoding problem. Try this

if(get_magic_quotes_gpc()){
   $param = stripslashes($row['your column name']);
}else{
  $param = $row['your column name'];
}

$param = json_decode(html_entity_decode($param),true);
$json_errors = array(
JSON_ERROR_NONE => 'No error has occurred',
JSON_ERROR_DEPTH => 'The maximum stack depth has been exceeded',
JSON_ERROR_CTRL_CHAR => 'Control character error, possibly incorrectly encoded',
JSON_ERROR_SYNTAX => 'Syntax error',
);
echo 'Last error : ', $json_errors[json_last_error()], PHP_EOL, PHP_EOL;
print_r($param);

So, html_entity_decode() worked for me. Please try this.

$input = file_get_contents("php://input");
$input = html_entity_decode($input);
$event_json = json_decode($input,true);

It took me like an hour to figure it out, but trailing commas (which work in JavaScript) fail in PHP.
This is what fixed it for me:

str_replace([PHP_EOL, ",}"], ["", "}"], $JSON);

I recommend creating a .json file (ex: config.json). Then paste all of your json object and format it. And thus you will be able to remove all of that things that is breaking your json-object, and get clean copy-paste json-object.

• I also face the same issue...
• I fix the following steps... 1) I print that variable in browser 2) Validate that variable data by freeformatter 3) copy/refer that data in further processing
• after that, I didn't get any issue.

It's probably BOM, as others have mentioned. You can try this:

    // BOM (Byte Order Mark) issue, needs removing to decode
    $bom = pack('H*','EFBBBF');
    $response = preg_replace("/^$bom/", '', $response);
    unset($tmp_bom);
    $response = json_decode($response);

This is a known bug with some SDKs, such as Authorize.NET

This happen because you use (') insted {") in your value or key.

Here is wrong format.

{'name':'ichsan'}

Thats will be return NULL if you decode them.

You should pass the json request like this.

{"name":"ichsan"}

I've solved this issue by printing the JSON, and then checking the page source (CTRL/CMD + U):

print_r(file_get_contents($url));

Turned out there was a trailing <pre> tag.

you should ensure these points

1. your json string dont have any unknowns characters

2. json string can view from online json viewer (you can search on google as online viewer or parser for json) it should view without any error

3. your string dont have html entities it should be plain text/string

for explanation of point 3

$html_product_sizes_json=htmlentities($html);
    $ProductSizesArr = json_decode($html_product_sizes_json,true);

to (remove htmlentities() function )

$html_product_sizes_json=$html;
    $ProductSizesArr = json_decode($html_product_sizes_json,true);

For my case, it's because of the single quote in JSON string.

JSON format only accepts double-quotes for keys and string values.

Example:

$jsonString = '{\'hello\': \'PHP\'}'; // valid value should be '{"hello": "PHP"}'
$json = json_decode($jsonString);
print $json; // null

I got this confused because of Javascript syntax. In Javascript, of course, we can do like this:

let json = {
    hello: 'PHP' // no quote for key, single quote for string value
}

// OR:
json = {
    'hello': 'PHP' // single quote for key and value
}

but later when convert those objects to JSON string:

JSON.stringify(json); // "{"hello":"PHP"}"

Before applying PHP related solutions, validate your JSON format. Maybe that is the problem. Try this online JSON format validator.

For me, I had to turn off the error_reporting, to get json_decode() working correctly. It sounds weird, but true in my case. Because there is some notice printed between the JSON string that I am trying to decode.

I had exactly the same problem But it was fixed with this code

$zip = file_get_contents($file);
$zip = json_decode(stripslashes($zip), true);

I had the same issue and none of the answers helped me. One of the variables in my JSON object had the value Andaman & Nicobar. I removed this & and my code worked perfectly.

<?php 
$json_url = "http://api.testmagazine.com/test.php?type=menu";
$json = file_get_contents($json_url);
$json=str_replace('},

]',"}

]",$json);
$data = json_decode($json);

echo "<pre>";
print_r($data);
echo "</pre>";
?>