Visual Studio ignore try catch - debug only

I think error handling is a good idea. :) When debugging it can get in the way - especially with nice user friendly messages. In VB6 I could just check a box for the compiler to ignore my error handling. I found the dialog that allows me to do something similar in VS, but it's about 10,000 check boxes instead of one - which is too many to change every time I want a production compilation.

Is there a way to set VS up so when I am in debugging mode I ge开发者_Go百科t one set of conditions and when I am in production I get another? ...or is there just another method to handling errors and debugging more efficiently?

Thanks

Try the Debug Menu and look at Exceptions. You can set it to automatically break when an exception is thrown.

In code, I'd probably just do something like:

#if !DEBUG
    try {
#endif
        DoSomething();
#if !DEBUG
    } catch (Exception ex) {
        LogEx(ex);
        throw new FriendlyException(ex);
    }
#endif

Or. more generally and with less #if:

#if DEBUG
   public const bool DEBUG = true;
#else
   public const bool DEBUG = false;
#endif

try {
   DoSomething();
} catch (Exception ex) {
   if (DEBUG) throw;
   LogEx(ex);
   throw new FriendlyException(ex);
}

Or, general purpose (like the Exception Handling library from P&P):

bool HandleException(Exception ex) {
    return !DEBUG;
}

But, if your real problem is just the Visual Studio GUI - just use a macro.

You can add this attribute to your methods:

[Conditional("DEBUG")]

You can also use #if #endif statements if you wish.