Convert seconds to Days, Minutes and Seconds

Hey everyone. I've continuing to learn C++ and I've been set the 'challenge' of converting seconds to format as the Days,Minutes and Seconds.

For example: 31600000 = 365 days, 46 minutes, 40 seconds.

using namespace std;
const int hours_in_day = 24;
const int mins_in_hour = 60;
const int secs_to_min = 60;

long input_seconds;
cin >> input_sec开发者_JAVA技巧onds;

long seconds = input_seconds % secs_to_min;
long minutes = input_seconds / secs_to_min % mins_in_hour;
long days = input_seconds / secs_to_min / mins_in_hour / hours_in_day;

cout << input_seconds << " seconds = "
     << days << " days, "
     << minutes << " minutes, "
     << seconds << " seconds ";

return 0;

It works and comes up with the correct answer but after completing it I looked at how other people had tackled it and theirs was different. I'm wondering If I'm missing something.

Thanks, Dan.

this seems to me to be the easiest way to convert seconds into DD/hh/mm/ss:

#include <time.h>
#include <iostream>
using namespace std;    

time_t seconds(1641); // you have to convert your input_seconds into time_t
tm *p = gmtime(&seconds); // convert to broken down time

cout << "days = " << p->tm_yday << endl;
cout << "hours = " << p->tm_hour << endl;
cout << "minutes = " << p->tm_min  << endl;
cout << "seconds = " << p->tm_sec << endl;

I hope it helps!

Regards,

Stoycho

One of the things about programming is that there is never just one way to do something. In fact if I were to set my mind to it, I might be able to come up with a dozen completely different ways to accomplish this. You're not missing anything if your code meets requirements.

For your amusement, here's a way to format up hours:minutes:seconds under Windows (elapsed is a double & represents number of seconds elapsed since... something)

sprintf_s<bufSize>(buf, "%01.0f:%02.0f:%02.2f", floor(elapsed/3600.0), floor(fmod(elapsed,3600.0)/60.0), fmod(elapsed,60.0));

I think is the challenge from Stephen Prata's book. I did it as follows:

#include <iostream>

using namespace std;

int main()
{
    long input_seconds = 31600000;

    const int cseconds_in_day = 86400;
    const int cseconds_in_hour = 3600;
    const int cseconds_in_minute = 60;
    const int cseconds = 1;

    long long days = input_seconds / cseconds_in_day;
    long hours = (input_seconds % cseconds_in_day) / cseconds_in_hour;
    long minutes = ((input_seconds % cseconds_in_day) % cseconds_in_hour) / cseconds_in_minute;
    long seconds = (((input_seconds % cseconds_in_day) % cseconds_in_hour) % cseconds_in_minute) / cseconds;
    cout << input_seconds << " seconds is " << days << " days, " << hours << " hours, " << minutes << " minutes, and " << seconds << " seconds.";

    cin.get();
    return 0;
}

For example: 31600000 = 365 days, 46 minutes, 40 seconds.

Really?

$ bc
365*24*60*60 + 46*60 + 40
31538800

365*24*60*60 + 1066*60 + 40
31600000

Did you mean "convert the input into days, hours, minutes and seconds, and then discard the hours" or "convert the input into days, total minutes within a day (i.e. can be more than 60), and seconds"?

In the second case I think you should replace the instruction for minutes with

long minutes = input_seconds / secs_to_min % (mins_in_hour * hours_in_day);