What does @_ -1 mean in Perl?

I'm trying to translate a Perl script to PHP and I'm having trouble with some Perl things. For instance, what does @_ -1 mean? And how do I write it in PHP?

The whole function is as follows:

sub variance {
    my $sum = sum_squares (@_);
    my $deg = @_ - 1;
    return $sum/$deg;
}

Ok, all the subroutines are as follows:

sub mean { # mean of values in an array
  my $sum = 0 ;
  foreach my $x (@_) {
    $sum += $x ;
  }
  return $sum/@_ ;
}

sub sum_squares { # sum of square differences from the mean
  my $mean = mean (@_) ;
  my $sum_squares = 0 ;
  foreach my $x (@_) {
    $sum_squares += ($x - $mean) ** 2 ;
  }
  return $sum_squares ;
}

sub variance { # variance of values in an array
  my $sum_squares = sum_squares (@_) ;
  my $deg_freedom = @_ - 1 ;
  return $sum_squares/$deg_freedom ;
}

sub median { # median of values in an array
  my @sorted = sort {$a <=> $b} (@_) ;
  if (1 == @sorted % 2) # Odd number of elements
    {return $sorted[($#sorted)/2]}
  else                   # Even number of elements
    {return ($sorted[($#sorted-1)/2]+$sorted[($#sorted+1)/2]) / 2}
}

sub histogram { # Counts of elements in an array
  my %histogram = () ;
  foreach my $value (@_) {$histogram{$value}++}
  return (%histogram) ;
}

Please bear with me because its my first time with Perl. From what I've seen (tested), the right answer in this case is the one of David Dorward. I 开发者_如何学Pythondo have another question regarding this set of subroutines that is here.

In this case,@_ is the arguments passed to the subroutine, as a list.

Taken in scalar context, it is the number of elements in that list.

So if you call: variance('a', 'b', 'c', 'd');, $deg will be 3.

Like already said, it is the array of arguments passed to the function. It's equivalent in PHP would be

• func_get_args() — Returns an array comprising a function's argument list
• func_num_args() — Returns the number of arguments passed to the function

The entire function would be

function variance() {
    $sum = sum_squares(func_get_args());
    $deg = func_num_args() - 1;
    return $sum/$deg;
}
// echo variance(1,2,3,4,5); // 13.75 (55/4)

For sum_squares, there is no native function in PHP. Assuming it does what the name implies, e.g. raising each argument to the power of 2 and then summing the result, you could implement it as

function sum_squares(array $args) {
    return array_reduce(
        $args, create_function('$x, $y', 'return $x+$y*$y;'), 0
    );
}
// echo sum_squares( array(1,2,3,4,5) ); // 55

Replace create_function with a proper lambda if you are on PHP5.3

It's the number of arguments, passed to the variance subroutine minus one (or index of the last element in the @_ array). @_ is used in scalar context here.

@_ is the incoming parameter to the sub, but referred in scalar context is the number of parameters.

In php will be something like:

function variance() {
    $arguments = func_get_args();
    $sum = sum_squares($arguments);
    $deg = sizeof($arguments);
    return $sum/$deg;
}

@_ is the list of parameters being paassed into the subroutine. When you use it in a non-scalar context such as:

sum_squares (@_)

you get the list, so presumably that would return the sum of the squares of all the numbers in that list (see comment below however).

When used in a scalar context, you get the length so in your case it would be the number of items in the $@ function list.

So your variance function is probably (I say probably since I don't have access to the sum_squares source code) calculating:

variance = arr[0]^2 + arr[1]^2 + ... + arr[N-1]^2
           --------------------------------------
                            N - 1

on the array of values being passed into your function.

I have to say that my understanding of variance is at odds with that (thouugh it's been a while since I did any stats). I'm pretty certain it's supposed to involve the sum of the squares of the differences between the values and the mean, not the values themselves. I suspect there's more happening inside sum_squares than its simple name implies.

To supplement the other answers, the @_ Special Variable is described in the free official Perl online documentation (along with other variables):

Within a subroutine the array @_ contains the parameters passed to that subroutine. See perlsub.

In function @_ will have list of function argument which is passed to the function . Actually when we are trying to assign the list value to the scalar , it will assign the length of the array. And Here -1 is for accessing the last element of the @_ array

sub test 
{ 
my $count = @_ ; # Now it will assign the number of function arguments 
# Because we are trying to assign as a scalar. 
>print "Output:$count\n" ; # Output : 4 
($count ) = @_   # Now it will assign the first element of the functions 
print "Output:$count\n" ; #  OUtput: 10 
# Because we are trying to assign as list values , So ,list as only one variable  . 
# So , first element gets assigned. 
} 
&test ( 10,20,30,40 ) ;