How can I write a leap-year program in one line using PHP?

How can I write a leap-year program in on开发者_JS百科e line using PHP?

This is how to know it using one line of code :)

print (date("L") == 1) ? "Leap Year" : "Not Leap Year";

if (($year % 400 === 0) || (($year % 100 !== 0) && ($year % 4 === 0))) echo "leap";

Since there is no limit in how long a line of code is, unless you are using a code convention like that of Zend Framework, you can use whatever works and write into one line. Of course, depending on the functionality of your leap-year program, this will likely be hard to maintain. I've seen legacy code running over 800 chars with PHP, HTML and CSS intermingled. Eye-bleeding, I can tell you.

echo date("L");

$nextyear  = mktime(0, 0, 0, date("m"),   date("d"),   date("Y")+1);

date("L"); is even shorter.

if(date("L")){
   //leap year
} else {
   //not leap year
}