Last but one Char in vb.net String

How do I find last but one cha开发者_高级运维racter in a vbstring

for e.g. In the string V1245-12V0 I want to return V

Don't use substring to get just one character

Dim MyString As String = "V1245-12V0"
Dim MyChar As Char = MyString(MyString.Length - 2)

Sorry it's been a while since I did VB so this may not be perfect (and is probably a mixture of C# and VB) but you get the idea:

Dim s = "V1245-12V0"
Dim lastButOneLetter = String.Empty

If s.Length > 1 Then
    'Can only get the last-but-one letter from a string that is minimum 2 characters
    lastButOneLetter = s.Substring(s.Length - 2, 1)
Else
    'do something if string is less than 2 characters
End If

EDIT: fixed to be compilable VB.NET code.

Dim secondToLastChar As Char 
secondToLastChar = Microsoft.VisualBasic.Strings.GetChar(mystring, mystring.Length - 2)

http://msdn.microsoft.com/en-us/library/4dhfexk4(VS.80).aspx

Or just remember that any string is an array of chars;

secondToLastChar = mystring(mystring.Length - 2)

If you want to get the last alpha-character in a string you could use a LINQ query such as (C#):

var d = from c in myString.ToCharArray().Reverse()
                where Char.IsLetter(c)
                select c;
return d.First();

string.Substring(string.Length - 2, 1);

Was it difficult?

dim mychar as string
dim yourstring as string
yourstring="V1245-12V0"
mychar=yourstring.Substring(yourstring.Length - 2, 1)

Use the Substring on the string s which contains 'V1245-12V0'

s.Substring(s.Length - 2, 1);

Here's a VB solution:

Dim text = "V1245-12V0"
Dim v = Left(Right(text, 2), 1)

You do not need to check the length of text, except for your semantics as to what you want to happen for empty (and Nothing) and single character strings.

You can have your own functions like

Function Left(ByVal str as string, byval index as integer) As String

    Left=str.Substring(0,index);
End Function

Function Right(ByVal str as string, byval index as integer) As String

    Right=str.Substring(str.Length-index)
End Function

And use them to get what you need.