sorting group of lines
I have a text file like below
iv_destination_code_10
TAP310_mapping_RATERUSG_iv_destination_code_10
RATERUSG.iv_destination_code_10 = WORK.maf_feature_info[53,6]
iv_destination_code_2
TAP310_mapping_RATERUSG_iv_destination_code_2
RATERUSG.iv_destination_code_2 = WORK.maf_feature_info[1,6]
iv_destination_code_3
TAP310_mapping_RATERUSG_iv_destination_code_3
RATERUSG.iv_destination_code_3 = WORK.maf_feature_info[7,6]
iv_destination_code_4
TAP310_mapping_RATERUSG_iv_destination_code_4
RATERUSG.iv_destination_code_4 = WORK.maf_feature_info[13,6]
iv_destination_code_5
TAP310_mapping_RATERUSG_iv_destination_code_5
RATERUSG.iv_destination_code_5 = WORK.maf_feature_info[19,6]
iv_destination_code_6
TAP310_mapping_RATERUSG_iv_destination_code_6
RATERUSG.iv_destination_code_6 = WORK.maf_feature_info[29,6]
iv_destination_code_7
TAP310_mapping_RATERUSG_iv_destination_code_7
RATERUSG.iv_destination_code_7 = WORK.maf_feature_info[35,6]
iv_destination_code_8
TAP310_mapping_RATERUSG_iv_destination_code_8
RATERUSG.iv_destination_code_8 = WORK.maf_feature_info[41,6]
iv_destination_code_9
TAP310_mapping_RATERUSG_iv_destination_code_9
RATERUSG.iv_destination_code_9 = WORK.maf_feature_info开发者_StackOverflow中文版[47,6]
combination of three lines form a unit:
iv_destination_code_9
TAP310_mapping_RATERUSG_iv_destination_code_9
RATERUSG.iv_destination_code_9 = WORK.maf_feature_info[47,6]
is one unit.
iv_destination_code_9
9 indicates the number by which i have to sort 10 9 8....
i need a shell script/awk which will sort the units in a descending order. how is it possible?
cat file | tr '\n' '#' | sed 's/]#/]\n/g' | sort -nrt_ -k4 | tr '#' '\n'
First all end of lines are replaced by #
, and end of lines at the end of blocks (]#
) are recreated.
Then a numeric reverse sort is performed on the fourth field with fields separated by _
.
Finally, original end of lines are retrieved.
sed 'N;N;s/\n/#/g' file |sort -t"_" -nr -k4 | sed 's|#|\n|g'
Or with gawk
awk -vRS="\niv_" -vFS="\n" 'BEGIN{t=0}
{
m=split($1,a,"_")
num[a[m]]
line[a[m]] = $0
}
END{
cmd="sort -nr"
for(i in num){ print i |& cmd }
close(cmd,"to")
while((cmd |& getline m) > 0) {
z=split(m,arr2,"\n")
}
close(cmd,"from")
print line[ arr2[1] ]
for(j=2;j<=z;j++){
if(line[ arr2[j]] != "" ){
print "iv_"line[ arr2[j] ]
}
}
}' file
This works similarly to mouvicel's answer, but uses non-printing characters as the special markers (and assumes that the original file doesn't contain them).
sed 's/]$/]'$'\1''/' text_file | tr '\1' '\0' | sort -znrt_ | tr '\0' '\n' | sed '/^$/d'
It assumes that there are no blank lines in the original file since it deletes them at the end. It also relies on every group-ending line to end in "]".
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