Java Get Multiple Items From Collection
Do Java collections have a built-in method to return multiple items from that collection? For example, the list below has n elements, some of which are duplicated in the list. How could I get all elements where the value = "one"? I realize it would be very easy to write my own method to achieve such functionality, I just wanted to make sure I am not missing a built in method to do this.
List<String> ls=new ArrayList&开发者_如何学Golt;String>();
ls.add("one");
ls.add("two");
ls.add("three");
ls.add("one");
ls.add("one");
//some type of built in function????
//ls.getItems("one");
//should return elements 0,3,4
Thanks
Google Collections have Predicates for this purpose.
In this example, it's enough to know the number of times "one" appears in the list, which you can get with java.util.Collections.frequency(ls, "one")
.
You could also have been using a Multiset
from google-collections, and called m.count("one")
, which would be much more efficient.
There isn't a built-in method, but Apache Commons has a select
method in CollectionUtils
that will get all the elements that match some criterion. Example usage:
List<String> l = new ArrayList<String>();
// add some elements...
// Get all the strings that start with the letter "e".
Collection beginsWithE = CollectionUtils.select(l, new Predicate() {
public boolean evaluate(Object o) {
return ((String) o).toLowerCase().startsWith("e");
}
);
I think you could do the trick of retaining the elements of this list which are in another list with the retainall method of Collection class link text. In the other list you can add only the "one" object.
List<String> ls=new ArrayList<String>();
ls.add("one");
ls.add("two");
ls.add("three");
ls.add("one");
ls.add("one");
List<String> listToCompare = new ArrayList<String>();
listToCompare.add("one");
ls.retainAll(listToCompare);
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