How to do an if statement on a function in PHP?
I just realized that you can't just use an if statement on a function, for example this doesn't work:
function sayHello()
{
echo "Hello World";
}
if(sayHello())
echo "Function Worked";
else
echo "Function Failed";
I also saw that a function can't be put as the value o开发者_如何学Cf a variable. So how can I do an if statement to check if a function has executed properly and display it to the browser?
It's not working since sayHello()
doesn't return anything place return true
in there or something.
if (sayHello() === FALSE)
echo "Function Failed";
else
echo "Function Worked";
this will work
<?php
$name1 = "bobi";
function hello($name) {
if($name == "bobi"){
echo "Hello Bob";
} else {
echo "Morning";
}
}
hello($name1);
?>
function selam($isim)
{
if ($isim == 'ugur') {
return 'Selam '.$isim.' :)';
}
return 'Sen kimsin kardes?';
}
echo selam('ugur');
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