How do I change my pwd to the real path of a symlinked directory?
Here's a rather elementary *nix question:
Given the following symlink creation:
ln -s开发者_StackOverflow /usr/local/projects/myproject/ myproject
... from my home directory /home/jvf/, entering the myproject symlink gives me a pwd /home/jfv/myproject/. Now, I would like to enter the parent directory of the directory I've symlinked to, but the cd .. command will only bring me back to my home directory /home/jfv/. Is there anyway to escape the symlink trail that I've entered, and instead have a pwd equal to the actual path of the myproject directory. That is, changing my pwd from /home/jfv/myproject/ into /usr/local/projects/myproject/?
Thanks :)
Just use -P
(physical) flag:
pwd -P
cd -P ..
If you do the following you should be OK.
1) First you follow your symlink:
[jfv@localhost ~]$ cd myproject
2) Now you execute the following command:
[jfv@localhost myproject]$ cd -P ./
3) Now, you can check your location and you will see that you are on the physical directory
[jfv@localhost myproject]$ pwd
The output will be as follows:
/usr/local/projects/myproject
Now, everything you do will be local and not on the symlink.
Programmatically, you would do this with the getcwd library function:
#include <unistd.h>
#include <stdio.h>
int main(int argc, char **argv)
{
char buf[1024*1024L];
char *cwd;
cwd = getcwd(buf, sizeof buf);
if (cwd == NULL) {
perror("getcwd");
return 1;
}
printf("%s\n", cwd);
return 0;
}
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