Why can't I open this XML in SAXParser?

public static void parseit(String thexml){
     SAXParserFactory factory = SAXParserFactory.newInstance();
     SAXParser saxParser;

    try {
        saxParser = factory.newSAXParser();
        DefaultHandler handler = new DefaultHandler() {
            public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAX开发者_如何转开发Exception {

            }
            public void endElement(String uri, String localName, String qName)throws SAXException {

            }           
            public void characters(char ch[], int start, int length) throws SAXException {

            }               
         };      
        saxParser.parse(thexml, handler);
        } catch (SAXException e) {
            e.printStackTrace();
        } catch (IOException e) {
            Log.e("e", "e", e);
            e.printStackTrace();
        }catch (ParserConfigurationException e) {
            e.printStackTrace();    
        }
}

This is my code. (many thanks to these guys: Can someone help me with this JAVA SAXParser?)

The problem is, I'm always getting into the IOException e. The message is this:

java.io.IOException: Couldn't open....and then my XML file.

My XML file is this, and it's a String:

<?xml version="1.0" encoding="UTF-8"?>
<result>
    <person>
        <first_name>Mike</first_name>
    </person>
</result>

Why can't it read my XML String?

The parse method you call expects an URI to the XML file to read.

What you might want to do instead is to create an InputSource from a StringReader like this:

InputSource source = new InputSource(new StringReader(thexml));
saxParser.parse(source, handler);

SAXParser's parse method expects a file name or URI as first argument, not an XML file read into a string.