Jquery next selector next() question
+----------------------------------------------------------------------+
| this is div .content |
| |
| +----------------+ |
| | .left_content | |
| | input inside | |
| +----------------+ |
| |
| |
| +------------+ |
| | span | |
| +------------+ |
| |
+----------------------------------------------------------------------+
Hello all, I'm trying to access the span element with jquery but I have some kind of error, here is the deal .content
is main div , .left_content
div is inside it and span
is inside .content
but outside .left_content
.
Now I can easily access span
by using .content span
, but since .content, .left_content and span are repeating throughout the website I wa开发者_如何学JAVAnt to access these elements by clicking on the input inside .left_content div
.
So finally I come to my question (from input inside .left_content perspective), how to get div .content
, .left_content
and span
selected?
So far what I've only managed to do is to get .left_content
selector by using $(this)parent('div:first')
This will do the trick:
$(this).closest("div.content").find("span")
Not sure what you mean, but:
$('input').click(function() {
var left_content = $(this).parent();
var content = left_content.parent();
var span = content.find('span');
});
精彩评论