开发者

zsh handling of arguments

In the zsh programming language,

how do I get the entire list of arguments as a string in "" ?

i.e. in

myzshcommand 1 2 3 foo bar

I 开发者_如何转开发want something to match me "1 2 3 foo bar"

Thanks!


Have you tried using $@?

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜