Display characters of a variable
I am doing a bash script and I want to displa开发者_如何转开发y the characters of a variable ($VAR). What I want the script to do is (pseudo-code) :
String var = "Hello";
for (int i = 0; i < var.length(); i++) {
System.out.println(var.substring(i, i+1));
}
The size of the variable can change, one time it can be 5 characters and the next time 6 for example.
Thank you for you help!
Michaël Here's a, hopefully quite close, translation.
var="Hello"
for (( i = 0; i < ${#var}; i++ ))
do
echo ${var:i:1}
done
Illustrates a few bash concepts.
${#var}
gives the number of characters in variable${var}
${var:x:y}
gives a substring of characters of${var}
starting at positionx
, lengthy
An alternate approach:
echo hello | sed 's/\(.\)/\1\n/g'
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