How to search for a character the displays as "<85>" in Vim
I have a file that was converted from EBCDIC to ASCII. Where there used to be new lines there are now characters that show up as <85>
(a symbol representing a single character, not the four characters it appears to be) and the whole file is on one line. I want to search for them and replace them all with new lines again, but I don't know how.
I tried putting the cursor over one and using * to search for the next occurrence, hoping that it might show up in my 开发者_如何学Go/
search history. That didn't work, it just searched for the word that followed the <85>
character.
I searched Google, but didn't see anything obvious.
My goal is to build a search and replace string like:
:%s/<85>/\n/g
Which currently just gives me:
E486: Pattern not found: <85>
I found "Find & Replace non-printable characters in vim" searching Google. It seems like you should be able to do:
:%s/\%x85/\r/gc
Omit the c
to do the replacement without prompting, try with c
first to make sure it is doing what you want it to do.
In Vim, typing :h \%x
gives more details. In addition to \%x
, you can use \%d
, \%o
, \%u
and \%U
for decimal, octal, up to four and up to eight hexadecimal characters.
For special character searching, win1252 for example, for the case of <80>
,<90>
,<9d>
...
type:
/\%u80, \/%u90, /\%u9d ...
from the editor.
Similarly for octal, decimal, hex, type: /\%oYourCode
, /\%dYourCode
, /\%xYourCode
.
try this: :%s/<85>/^M/g
note: press Ctrl-V together then M
or if you don't mind using another tool,
awk '{gsub("<85>","\n")}1' file
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