Matching all words except one
Say I have a sentence:
I am a good buy and bad boy too
How to select every word except boy in this sentence using reg开发者_如何学编程ular expression ?
You can use negative look behind:
\w+\b(?<!\bboy)
Or negative look ahead since not all support negative look behind
(?!boy\b)\b\w+
You can read about negative look ahead here
Try:
\b(?!boy\b).*?\b
which means:
- Zero width word break (
\b
) - That isn't followed by "boy" and another word break;
- followed by any characters in a non-greedy way;
- Up until another word break.
Note: the word break matches the start of the string, the end of the string and any transition from word (number, letter or underscore) to non-word character or vice versa.
/\b(?!boy)\S+/g
If you use "boy" as splitter, you would get remaining parts. You could use those as selection keys.
>>> re.split("boy","I am a good buy and bad boy too")
['I am a good buy and bad ', ' too']
Substitute boy to nothing... in Perl that would be:
s/boy //g
I tested the following with http://regex101.com:
\b(?!boy)\S+|\w*\b$
This provides the list of all words delimited by spaces, but excludes only the word "boy" as asked.
As alternative, if possessive quantifiers are available, you can use;
\w++(?<!boy)
It takes generally less steps than using world boundaries.
Which language? Why do you want to use a regex?
answer = yourString.Replace( "boy", "" );
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