Oracle find a constraint
I have a constraint called users.SYS_C00381400
. How d开发者_如何学JAVAo I find what that constraint is? Is there a way to query all constraints?
select * from all_constraints
where owner = '<NAME>'
and constraint_name = 'SYS_C00381400'
/
Like all data dictionary views, this a USER_CONSTRAINTS view if you just want to check your current schema and a DBA_CONSTRAINTS view for administration users.
The construction of the constraint name indicates a system generated constraint name. For instance, if we specify NOT NULL in a table declaration. Or indeed a primary or unique key. For example:
SQL> create table t23 (id number not null primary key)
2 /
Table created.
SQL> select constraint_name, constraint_type
2 from user_constraints
3 where table_name = 'T23'
4 /
CONSTRAINT_NAME C
------------------------------ -
SYS_C00935190 C
SYS_C00935191 P
SQL>
'C'
for check, 'P'
for primary.
Generally it's a good idea to give relational constraints an explicit name. For instance, if the database creates an index for the primary key (which it will do if that column is not already indexed) it will use the constraint name oo name the index. You don't want a database full of indexes named like SYS_C00935191
.
To be honest most people don't bother naming NOT NULL constraints.
To get a more detailed description (which table/column references which table/column) you can run the following query:
SELECT uc.constraint_name||CHR(10)
|| '('||ucc1.TABLE_NAME||'.'||ucc1.column_name||')' constraint_source
, 'REFERENCES'||CHR(10)
|| '('||ucc2.TABLE_NAME||'.'||ucc2.column_name||')' references_column
FROM user_constraints uc ,
user_cons_columns ucc1 ,
user_cons_columns ucc2
WHERE uc.constraint_name = ucc1.constraint_name
AND uc.r_constraint_name = ucc2.constraint_name
AND ucc1.POSITION = ucc2.POSITION -- Correction for multiple column primary keys.
AND uc.constraint_type = 'R'
AND uc.constraint_name = 'SYS_C00381400'
ORDER BY ucc1.TABLE_NAME ,
uc.constraint_name;
From here.
maybe this can help..
SELECT constraint_name, constraint_type, column_name
from user_constraints natural join user_cons_columns
where table_name = "my_table_name";
I found this one to be the most helpful:
select * from ALL_CONS_COLUMNS
where constraint_name = 'SYS_C00381400';
It returns both table and column name, e.g.
OWNER,CONSTRAINT_NAME,TABLE_NAME,COLUMN_NAME,POSITION
MY_OWNER,SYS_C00381400,MY_TABLE,MY_COLUMN,1
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