Keeping Duplicates

I have an IEnumerable containing objects that have a groupnumber property. I want to be able to get a list of all objects that have duplicate groupnumbers e.g.

obj1: groupnumber=1 KEEP

obj2: groupnumber=2 DELETE

obj3: groupnumber=1 KEEP

I can use the following to get a list of all the duplicated groupnumbers

   var duplicates = from c in sorted 
                    group c by c.groupnumber into g 
                    where g.开发者_Go百科Count() > 1 
                    select new { groupnumber = g.Key, recs = g.Count() };

but I cant figure out how to get a list cleaned of all the single instance objects

Cheers

Alright, I had to read your question a few times. My understanding is that you want to "select all the objs where there are more than one obj in the collection with the same groupnumber"... so filter out the ones with unique groupnumbers.

If that's the case, you're almost there! Use SelectMany to collapse the groups into a single collection.

var duplicates = (from c in sorted
    group c by c.groupnumber into g
    where g.Count() > 1
    select g).SelectMany(grp => grp);

Here's the simplest option (I think):

sorted.GroupBy( c => c.groupnumber )
      .Where( g => g.Count() > 1 )
      .SelectMany( g => g );

Alternatively, try the following:

var duplicates = from c in sorted 
                 group c by c.groupnumber into g 
                 where g.Count() > 1
                 select g.Key;

// convert the list to a lookup object for efficiency
var dupLookup = duplicates.ToLookup( c => c );

// exclude all items that are NOT one of the duplicate group keys
var excludeNonDups = sorted.Where( c => !dupLookup.Contains( c ) )

Add in a call to Distinct() if you only want one of each of the duplicates:

var duplicates = (from c in sorted 
                  group c by c.groupnumber into g 
                  where g.Count() > 1 
                  select new { groupnumber = g.Key, recs = g.Count() }).Distinct();