Assembly how to translate JNE to C Code without ZF flag access
ASM to C Code emulating nearly done.. just trying to solve these second pass problems.
Lets say I got this ASM function
401040 MOV EAX,DWORD PTR [ESP+8]
401044 MOV EDX,DWORD PTR [ESP+4]
401048 PUSH ESI
401049 MOV ESI,ECX
40104B MOV ECX,EAX
40104D DEC EAX
40104E TEST ECX,ECX
401050 JE 401083
401052 PUSH EBX
401053 PUSH EDI
401054 LEA EDI,[EAX+1]
401057 MOV AX,WORD PTR [ESI]
40105A XOR EBX,EBX
40105C MOV BL,BYTE PTR [EDX]
40105E MOV ECX,EAX
401060 AND ECX,FFFF
401066 SHR ECX,8
401069 XOR ECX,EBX
40106B XOR EBX,EBX
40106D MOV BH,AL
40106F MOV AX,WORD PTR [ECX*2+45F81C]
401077 XOR AX,BX
40107A INC EDX
40107B DEC EDI
40107C MOV WORD PTR [ESI],AX
40107F JNE 401057
401081 POP EDI
401082 POP EBX
401083 POP ESI
401084 RET 8
My program would create the following for it.
int Func_401040() {
regs.d.eax = *(unsigned int *)(regs.d.esp+0x00000008);
regs.d.edx = *(unsigned int *)(regs.d.esp+0x00000004);
regs.d.esp -= 4;
*(unsigned int *)(regs.d.esp) = regs.d.esi;
regs.d.esi = regs.d.ecx;
regs.d.ecx = regs.d.eax;
regs.d.eax--;
if(regs.d.ecx == 0)
goto label_401083;
regs.d.esp -= 4;
*(unsigned int *)(regs.d.esp) = regs.d.ebx;
regs.d.esp -= 4;
*(unsigned int *)(regs.d.esp) = regs.d.edi;
regs.d.edi = (regs.d.eax+0x00000001);
regs.x.ax = *(unsigned short *)(regs.d.esi);
regs.d.ebx ^= regs.d.ebx;
开发者_开发技巧 regs.h.bl = *(unsigned char *)(regs.d.edx);
regs.d.ecx = regs.d.eax;
regs.d.ecx &= 0x0000FFFF;
regs.d.ecx >>= 0x00000008;
regs.d.ecx ^= regs.d.ebx;
regs.d.ebx ^= regs.d.ebx;
regs.h.bh = regs.h.al;
regs.x.ax = *(unsigned short *)(regs.d.ecx*0x00000002+0x0045F81C);
regs.x.ax ^= regs.x.bx;
regs.d.edx++;
regs.d.edi--;
*(unsigned short *)(regs.d.esi) = regs.x.ax;
JNE 401057
regs.d.edi = *(unsigned int *)(regs.d.esp);
regs.d.esp += 4;
regs.d.ebx = *(unsigned int *)(regs.d.esp);
regs.d.esp += 4;
label_401083:
regs.d.esi = *(unsigned int *)(regs.d.esp);
regs.d.esp += 4;
return 0x8;
}
Since JNE 401057 doesn't use the CMP or TEST
How do I fix that use this in C code?
The most recent instruction that modified flags is the dec, which sets ZF when its operand hits 0. So the jne is about equivalent to if (regs.d.edi != 0) goto label_401057;.
BTW: ret 8 isn't equivalent to return 8. The ret instruction's operand is the number of bytes to add to ESP when returning. (It's commonly used to clean up the stack.) It'd be kinda like
return eax;
regs.d.esp += 8;
except that semi-obviously, this won't work in C -- the return makes any code after it unreachable.
This is actually a part of the calling convention -- [ESP+4] and [ESP+8] are arguments passed to the function, and the ret is cleaning those up. This isn't the usual C calling convention; it looks more like fastcall or thiscall, considering the function expects a value in ECX.
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