PHP GD imagecopyresampled() and flip it horizontal
I'm rendering a PNG image from another PNG image with imagecopyresampled(). Now i want some parts of the image to be flipped horizontal, so i have tried this:
//horizontal
$src_x = $width - 1;
$src_width = -$width;
imagecopyresampled(
$imgdest, $imgsrc, 0, 0, $src_x, $src_y , $width, $height
, $src_width, $src_height
);
Taken from a user-comment from the PHP Manual.
It does not work in my case (where I 开发者_开发问答copy a lot of pieces from the original image to the new), instead it copies another piece of the image. Does anyone has a solution to this?
I know this is a little late but I was looking for this solution myself too and just found the code needed...
function image_flip($img, $type=''){
$width = imagesx($img);
$height = imagesy($img);
$dest = imagecreatetruecolor($width, $height);
switch($type){
case '':
return $img;
break;
case 'vert':
for($i=0;$i<$height;$i++){
imagecopy($dest, $img, 0, ($height - $i - 1), 0, $i, $width, 1);
}
break;
case 'horiz':
for($i=0;$i<$width;$i++){
imagecopy($dest, $img, ($width - $i - 1), 0, $i, 0, 1, $height);
}
break;
case 'both':
for($i=0;$i<$width;$i++){
imagecopy($dest, $img, ($width - $i - 1), 0, $i, 0, 1, $height);
}
$buffer = imagecreatetruecolor($width, 1);
for($i=0;$i<($height/2);$i++){
imagecopy($buffer, $dest, 0, 0, 0, ($height - $i -1), $width, 1);
imagecopy($dest, $dest, 0, ($height - $i - 1), 0, $i, $width, 1);
imagecopy($dest, $buffer, 0, $i, 0, 0, $width, 1);
}
imagedestroy($buffer);
break;
}
return $dest;
}
Okay so many years after I found the answer myself, so I just wanted to let anybody else know.
It was pretty simple, example:
Instead of:
imagecopy($output, $input, 8, 20, 4, 20, 4, 12)
I would use:
imagecopyresampled($output, $input, 8, 20, (8 - 1), 20, 4, 12, 0 - 4, 12);
Which would flip the part of the image horizontal.
I use that:
imageflip ( resource $image , int $mode ) : bool
https://www.php.net/manual/es/function.imageflip.php
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