Join Last Record Based on TimeStamp
I have a access log, which records usernames and a timestamp at various points in the application. I want to see if I can approximate the amount of time they are spending in the application. Basically I want to join 开发者_运维知识库each record to the last access record based on the timestamp, so I can figure out the time difference.
I can't think of how to join to the first record whose timestamp is less than the current record. What is the way to do this?
Try something like this:
SELECT A.UserName, A.EntryDate, DATEDIFF(ss,A.EntryDate, B.EntryDate) SecondsDuration
FROM YourTable A
OUTER APPLY (SELECT MAX(EntryDate) EntryDate
FROM YourTable
WHERE UserName = A.UserName AND EntryDate < A.EntryDate) B
I can't think of how to join to the first record whose timestamp is less than the current record. What is the way to do this?
You almost gave yourself the answer:
Something similar to below should work:
SELECT
lt.*,
lastentry.timeofEntryColumn,
DATEDIFF( second, lt.timeofEntryColumn, lt.timeofEtnryColumn) AS DifferenceinSeconds
FROM logTable lt
LEFT OUTER JOIN logtable AS lastentry
ON lastentry.ID = (SELECT TOP 1 ID FROM logtable lt2
WHERE lt2.timeofEntryColumn < lt.timeofEntryColumn
ORDER BY lt2.timeofEntryColumn desc)
Of course, you should add some more to this: maybe a condition to the outer join that requires the userID match...
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