Detecting colors for an Image using PHP
How can I detect the top 2 开发者_如何学Gocolors of an Image in PHP?
for example I have this image:
This function/process will return: 0000FF or blue and FFFF00 or YELLOW
Thanks
Here's a script that will give you the list:
function detectColors($image, $num, $level = 5) {
$level = (int)$level;
$palette = array();
$size = getimagesize($image);
if(!$size) {
return FALSE;
}
switch($size['mime']) {
case 'image/jpeg':
$img = imagecreatefromjpeg($image);
break;
case 'image/png':
$img = imagecreatefrompng($image);
break;
case 'image/gif':
$img = imagecreatefromgif($image);
break;
default:
return FALSE;
}
if(!$img) {
return FALSE;
}
for($i = 0; $i < $size[0]; $i += $level) {
for($j = 0; $j < $size[1]; $j += $level) {
$thisColor = imagecolorat($img, $i, $j);
$rgb = imagecolorsforindex($img, $thisColor);
$color = sprintf('%02X%02X%02X', (round(round(($rgb['red'] / 0x33)) * 0x33)), round(round(($rgb['green'] / 0x33)) * 0x33), round(round(($rgb['blue'] / 0x33)) * 0x33));
$palette[$color] = isset($palette[$color]) ? ++$palette[$color] : 1;
}
}
arsort($palette);
return array_slice(array_keys($palette), 0, $num);
}
$img = 'icon.png';
$palette = detectColors($img, 6, 1);
echo '<img src="' . $img . '" />';
echo '<table>';
foreach($palette as $color) {
echo '<tr><td style="background:#' . $color . '; width:36px;"></td><td>#' . $color . '</td></tr>';
}
echo '</table>';
If you are OK to call an external utility, Imagemagick can generate a histogram for you. It's probably going to be much faster than a PHP implementation.
Basically, this command gives you a list of colours, sorted by most dominant first:
convert 'http://i.stack.imgur.com/J2txV.png' -format %c histogram:info:-|sort -r
You might want to map the image to a fixed palette first ("Round off" the colours). This is what I use:
convert 'http://i.stack.imgur.com/J2txV.png' -modulate 100,200,100 -remap 'http://i.stack.imgur.com/GvTqB.png' -format %c histogram:info:-|sort -r
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