开发者

Sort mysql results based on data from another table in Kohana

I inherited this Kohana project and have little experience with it and ORM.

Table structure is like this:

ROLES TABLE
id
name
ROLES_USERS TABLE
role_id
user_id
USERS TABLE
id
email
password
last_login

The thing is, I need to get users sorted by whether they have a certain role (login in this case) but have no idea how to do that with ORM.

Current query is:

$users = ORM::factory('user')
    ->limit($pagination->items_per_page)
    ->offset($pagination->offset)
    ->order_by('last_login', 'DESC')
    ->find_all();

and then when outputting it's printed like this:

$row['status'][] = ($user->has('roles', ORM::factory('role', array('name' => 'login')))
    ? '<span class="green">Active</span>'
    : '<spa开发者_开发知识库n class="red">Blocked</span>');

So the question would be how to alter the query to be able to sort by whether users are allowed to login or not.


$users = ORM::factory('user')
    ->join('roles_users', 'LEFT')
        ->on('roles_users.user_id', '=', 'user.id')
    ->join('roles', 'LEFT')
        ->on('roles_users.role_id', '=', DB::expr("roles.id AND roles.name = 'login'"))
    ->group_by('user.id')
    ->order_by('IFNULL("roles.id", \'2000\')', 'ASC')
    ->find_all()

I hope you don't have 2000 roles, but active users should come first using this query


Maybe you could just get the users for the login role?

$login_users = ORM::factory('role', array('name'=>'login'))->users->find_all();
0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜