sed: Delete blank lines following line ending with a marker
How do I do this using sed
?
Input: Expected output:
1 | 1
2 MARKER | 2 MARKER
| 3 MARKER
| 4
|
| 5 MARKER
| 6
|
3 MARKER | 开发者_开发技巧
| 7 MARKER
4 | 8
| 9
5 MARKER |
6 |
|
|
7 MARKER |
|
8 |
9 |
First I tried this: It doesn't work coz "# niether t or b work because d causes the script to break."
/MARKER$/ {
# i -- Line with MARKER
:my_branch
# i -- in branch
# write current patt space to output and read next line to pattern space
n
# if non blank goto EO script
/^$/! b
# if blank line delete it
/^$/ d
# loop back for more blank lines.
t my_branch
# niether t or b work because d causes the script to break.
b my_branch
}
then I tried this, which almost works :((( -- it doesn't remove the line between 3 and 4, which I think is because 3 is consumed during the processing of 2 and thus it's marker is missed.
/MARKER$/ {
# i -- Line with MARKER
:my_branch
# i -- in branch
N
s/MARKER\n/MARKER/
t my_branch
# I added the following but it doesn't help..
/MARKER$/ b my_branch
}
there 4-5 other versions I tried, but none worked.
I did all this because I was trying to answer this question: replace two newlines to one in shell command line, so I started learning sed from http://sed.sourceforge.net/sed1line.txt and http://www.grymoire.com/Unix/Sed.html
IOW I know there are solutions using awk, perl etc but I just wanted to learn using sed.
Thanks.
see below, I think it is what you want: (it ran on my linux box with gnu sed)
kent$ cat t
1
2 MARKER
3 MARKER
4
5 MARKER
6
7 MARKER
8
9
kent$ sed -r ':a;N;s/(.*MARKER)\s+(\n.*)/\1\2/;ba;' t
1
2 MARKER
3 MARKER
4
5 MARKER
6
7 MARKER
8
9
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