What is the fastest way to copy a double[] in Java? [duplicate]
Simple question, what's the fastest way of copying an array of doubles in Java. I currently do this...
public static double[] clone_doubles(double[] from)
{
double[] to = new double[from.length];
for (int i = 0; i < from.length; i++) to[i] = from[i];
return to;
}
which also does the allocation to avoid overflows, but if there is a quicker way I will separate the allocation from the copy.
I have looked at Arrays.copyOf()
and System.arraycopy()
but I'm wondering if anyone has any neat tricks.
Edit:
How about copying a double[][]
?
Java Practices did a comparison of different copy methods on arrays of int
:
Here are the results from their site:
java -cp . -Xint ArrayCopier performance 250000
Using clone: 93 ms
Using System.arraycopy: 110 ms
Using Arrays.copyOf: 187 ms
Using for loop: 422 ms
Looks to me like a tie between System.arraycopy()
and clone()
.
System.arraycopy
is probably your best bet if you just want to copy from one array to another.
Otherwise
public static double[] clone_doubles(double[] from) {
return (double[]) from.clone();
}
will give you a clone.
System.arraycopy() is your best bet. Generally, it's implemented with native instructions, probably involving direct calls to the operating system's memory manager.
In Java 6 the performance of arraycopy was improved as "hand-coded assembly stubs are now used for each type size when no overlap occurs".
Read this other post for further details.
Arrays.copy, [].clone and System.arraycopy w/ new object are using the same code path when properly JIT.
Here is the corresponding bug: http://bugs.sun.com/view_bug.do?bug_id=6428387
public static double[] clone_doubles(double[] from)
{
return Arrays.copyOf(from, from.length);
}
This is internally implemented using System.arrayCopy()
:
public static double[] copyOf(double[] original, int newLength) {
double[] copy = new double[newLength];
System.arraycopy(original, 0, copy, 0,
Math.min(original.length, newLength));
return copy;
}
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