In Javascript, why is [1, 2] == [1, 2] or ({a : 1}) == ({a : 1}) false? [duplicate]
The following is done in Firebug:
>>> [1, 2] == [1, 2]
false
>>> ({a : 1}) == ({a : 1})
false
I thought Javscript has some rule that says, if an Ob开发者_运维技巧ject or Array has the same references to the same elements, then they are equal?
But even if I say
>>> foo = {a : 1}
Object { a=1}
>>> [foo] == [foo]
false
>>> ({a: foo}) == ({a: foo})
false
Is there a way to make it so that it can do the element comparison and return true
?
{ }
and [ ]
are the same as new Object
and new Array
And new Object != new Object
(ditto with Array
) because they are new and different objects.
If you want to know whether the content of two arbitary objects is the "same" for some value of same then a quick (but slow) fix is
JSON.parse(o) === JSON.parse(o)
A more elegant solution would be to define an equal function (untested)
var equal = function _equal(a, b) {
// if `===` or `==` pass then short-circuit
if (a === b || a == b) {
return true;
}
// get own properties and prototypes
var protoA = Object.getPrototypeOf(a),
protoB = Object.getPrototypeOf(b),
keysA = Object.keys(a),
keysB = Object.keys(b);
// if protos not same or number of properties not same then false
if (keysA.length !== keysB.length || protoA !== protoB) {
return false;
}
// recurse equal check on all values for properties of objects
return keysA.every(function (key) {
return _equal(a[key], b[key]);
});
};
equals
example
Warning: writing an equality function that "works" on all inputs is hard, some common gotchas are (null == undefined) === true
and (NaN === NaN) === false
neither of which I gaurd for in my function.
Nor have I dealt with any cross browser problems, I've just assumed ES5 exists.
To see what kind of code is necessary to do the deep equality you are talking about, check out Underscore.js's _.isEqual
function or QUnit's deepEqual
implementation.
Its because javascript object literals do not share the same pointers. Instead a new pointer gets created for each one. Consider the following example:
>>> ({a : 1}) == ({a : 1})
false
... but ...
>>> obj = ({a : 1});
Object
>>> obj == obj
true
obj
is a pointer to the litteral object { a : 1 }
. So this works because the pointers are the same when you compare them
You are comparing different objects.
>>> var a = [1,2] var b = [1,2]
>>> a == b
false
>>> a == a
true
If you want to test array equality you might want to use some library or just write the test yourself.
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