How to get css class name using Selenium?

I am new in seleni开发者_运维知识库um testing. I want to get the css class name using selenium. I am using eclipse and Java for development.

<table >
<tr class="odd"><td>Odd row</td></tr>
<tr class="even"><td>Even row</td></tr>
<tr class="odd"><td>Odd row2</td></tr>
<tr class="even"><td>Even row2</td></tr>       
</table>

Is there any way to get the class name 'odd' or 'even' using selenium? I

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From a WebElement you can use the getAttribute method like this:

element.getAttribute("class")

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Yes, you can use getAttribute(attributeLocator) function for the your requirement.

 selenium.getAttribute(//xpath@class);

Specify the Xpath of the element for which you require to know the class of.

Thanks.

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There is nothing depending on eclipse or java, in fact it is more about location strategy. If you want to access specific tr element with/without css class you can use css locator:

css=tr:nth(indx_base_0)

nth row with class

css=tr.odd:nth(indx_base_0)

first row with class odd

css=tr.odd

Using xpath:

//tr[index_base_1]

first row with class odd

//tr[@class='odd']

nth row with class odd

//tr[@class='odd'][index_base_1]

Here are some useful examples

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In context of the code snippet, say you want to get the class "odd" for the first row in the table.
You can follow the below steps:
(Note:- Assuming there is one table in your webpage)

1- Get the element first:

WebElement ele = driver.findElement(By.xpath("//table/tr[1]"));

The above code uses the xpath to get the element, i.e., the first row of the table.

2- Then, get the attribute "class" of the element using "getAttribute" method:

String class_name = ele.getAttribute("class");

The above code will fetch the "class" name of the related element and assign it to the String variable "class_name" for further use

Similarly, for getting "even" class, which is the attribute for fourth row of table , you can use the below code:

ele = driver.findElement(By.xpath("//table/tr[4]"));
class_name = ele.getAttribute("class");

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If CSS is your requirement, and in the absence of additional/differentiating element attributes, try the following (in the example, I have used simple text assertions):

assertEquals(selenium.getText("css=tr.odd > td"), "Odd row");
assertEquals(selenium.getText("css=tr.even > td"), "Even row");
assertEquals(selenium.getText("//tr[3]/td"), "Odd row2");
assertEquals(selenium.getText("//tr[4]/td"), "Even row2");

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Getting the CSS class name using Selenium using C#:

string _className;
IWebElement _ele = _driver.FindElement(By.Xpath("Xpath of Element"));
_className = _ele.GetAttribute("AttributeName Here");