New/delete[] and VirtualAlloc
#include <Windows.h>
#include <iostream>
using namespace std;
int main(void)
{
unsigned char* pFoo = new unsigned char[1000];
pFoo = (unsigned char*)VirtualAlloc(NULL, 1000, MEM_COMMIT, PAGE_EXECUTE_READWRITE);
VirtualFree(pFoo, 0, MEM_RELEASE);
delete[] pFoo;
cin.ignore();
cin.get();
return 0;
}
开发者_高级运维This crashes for me at
delete[] pFoo;
I know this is crashing because of VirtualAlloc but I'm not sure how to fix this...
You're using the same variable. So your first allocation gets leaked.
After you free it with VirtualFree
, the pointer is invalid. So delete
on it is undefined.
Furthermore:
You can't mix VirtualAlloc
and delete
for the same reason you can't mix malloc
with delete
.
unsigned char* pFoo = new unsigned char[1000];
Now pFoo
holds a pointer to dynamic memory.
pFoo = (unsigned char*)VirtualAlloc(NULL, 1000, MEM_COMMIT, PAGE_EXECUTE_READWRITE);
This overwrites the old pointer, the 1000 char
array is leaked.
Try:
unsigned char* pFoo = new unsigned char[1000];
unsigned char* pBar = (unsigned char*)VirtualAlloc(NULL, 1000, MEM_COMMIT, PAGE_EXECUTE_READWRITE);
VirtualFree(pBar, 0, MEM_RELEASE);
delete[] pFoo;
Either use new/delete or VirtualAlloc/VirtualFree. You are allocating two separate memory blocks, using pFoo to refer to both (when of course it can only refer to one at a time) and then calling the two free functions with pFoo. One of those is going to fail :)
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