Fileupload copying file to 2. directory

I'm trying to make a file_upload of images, where I want the script to add the image to one folder called: foto, AND then I wan't it to copy the same image to: foto_ikon.

How can I do this?

I think I have to use the copy() but I don't know how to, really.

move_uploaded_file($_FILES["file"]["tmp_name"],"../foto/" . $_FILES["file"]["name"]);

This is how my move_uploaded_file looks like. 开发者_开发百科

It works perfectly.

I've tried to do it like this:

move_uploaded_file($_FILES["file"]["tmp_name"],"../foto/" . $_FILES["file"]["name"]);
copy($_FILES["file"]["name"], "../foto_ikon/");

But it's not the right way, I see.

After you've performed move_uploaded_file there is no file at $_FILES["file"]["name"] anymore (that is why actually function is named move_uploaded_file)(and as DaveRandom mentioned - there was no file ever).

So if you need to copy it - do that using its real current location (the place you've moved the original file to) "../foto/" . $_FILES["file"]["name"] like this:

copy("../foto/" . $_FILES["file"]["name"], "../foto_ikon/" . $_FILES["file"]["name"]);

Simple, you moved the file from TMP to "../foto/", copy it from there, not from your current directory:

move_uploaded_file($_FILES["file"]["tmp_name"],"../foto/" . $_FILES["file"]["name"]);
copy("../foto/" . $_FILES["file"]["name"], "../foto_ikon/" . $_FILES["file"]["name"]);