PHP: $ get inside
So I want Get the part of url into a php This is my script
I want $_GET["m"]
Insidr of
<?php include('links.php'); ?>
<?php echo $title ?>
<?php include('links开发者_JAVA百科.php'); ?>
<ul class="pageitem"><li class="textbox"><p> the codes go here</p></li></ul>
Teh codes are in dere:
<?php include('links.php'); ?>
<?php echo $title ?>
<?php include('links.php'); ?>
<ul class="pageitem"><li class="textbox"><p><?php echo $_GET["m"]; ?></p></li></ul>
But you seemed to have $title
printing just fine. Is this what you're looking for? I'm not exactly sure of what you are asking.
$_GET
is a Superglobal in PHP. You can use it anywhere...
<?php include('links.php'); ?>
<?php echo $title; ?>
<?php include('links.php'); /* Is the double include intended? */ ?>
<ul class="pageitem">
<li class="textbox">
<p>
I like a having my <?php echo $_GET['m']; ?>
in the morning. Who doesn't
like <?php echo $_GET['m']; ?> in the morning anyway?
</p>
</li>
</ul>
精彩评论