django RadioSelect widget list id
I currently have a RadioSelect widget on one of my form classes that I want to style with css. However the rendered widget is contai开发者_JAVA技巧ned in an ul
and the list has no id.
What is the easiest way to add an id to the rendered list?
Subclass RadioFieldRenderer
and override render
method.
RadioFieldRenderer
is an object used by RadioSelect to enable customization of radio widgets.
Example implementation that adds class to ul
element:
from django.utils.encoding import force_unicode
from django.utils.safestring import mark_safe
class MyRadioFieldRenderer(forms.widgets.RadioFieldRenderer):
def render(self):
"""Outputs a <ul> for this set of radio fields."""
return mark_safe(u'<ul class="inputs-list">\n%s\n</ul>' %
u'\n'.join([u'<li>%s</li>'
% force_unicode(w) for w in self]))
Usage:
field = forms.ChoiceField(label=_('field'),
choices=FIELD_CHOICES,
widget=forms.widgets.RadioSelect(
renderer=MyRadioFieldRenderer
)
)
I have no solution to modify rendered html. But you can put rendered html inside a tag with id (or a class in my case):
<td class="tria_tag" >
<ul>
<li><label for="id_935591-estat_0"><input checked="checked" name="935591-estat" value="2" id="id_935591-estat_0" type="radio" class="presenciaEstat" /> Present</label></li>
<li><label for="id_935591-estat_1"><input value="3" type="radio" class="presenciaEstat" name="935591-estat" id="id_935591-estat_1" /> Falta</label></li>
<li><label for="id_935591-estat_2"><input value="4" type="radio" class="presenciaEstat" name="935591-estat" id="id_935591-estat_2" /> Justificada</label></li>
<li><label for="id_935591-estat_3"><input value="5" type="radio" class="presenciaEstat" name="935591-estat" id="id_935591-estat_3" /> Retràs</label></li>
</ul>
</td>
and then with jquery you can access to :
$('.tria_tag').each(
function(index) {
ul=$(this).children().first();
...
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