find with exec : how to perform multistep conditional action on each file

I have bunch of php files in directory structure say /mylibs

I want to run a simple php -l $file on each php file which checks for syntax errors

find /mylibs -type f -iname "*.php" -exec php -l {} &>/dev/null \;

thats step one, the &>/dev/null eats verbose output from php (found syntax errors or not)

The php -l returns 0 if no error is found depending upon which, I want to copy them to some other dir say /mybin. To check if this works as expected I tried

find /mylibs -type f -iname "*.php" -ok php -l {} &>/dev/null ; echo $? \;

but this simply prints 1 on the terminal and开发者_Go百科 does not ask for confirmation (-ok acts same as -exec after interactive confirmation)

What am I doing wrong here ? is it not possible to do this?

You can use a while loop:

find /mylibs -type f -iname "*.php" | while IFS= read -r path
do
    php -l "$path" &>/dev/null
    if [ $? -eq 0 ]
    then
        cp "$path" /mybin
    fi
done

does this work for u?

 find ....|xargs awk '{r=system("php -l "$0" &>/dev/null"); if(!r) system("cp "$0" /path/to/targetDir")}'