MS Access 2007 Append query trouble
I have an append query that is trying to append some records to one of my tables. However, I am getting an error that says “didn’t add 1200 records due to key violations.” 1200 is the total number of records I am trying to append. I don’t understand why I am getting this error because all of my columns in the destination table allow duplicates (even though this append query doesn’t duplicate any information), and if I copy the structure of the table and append the records to that, everything works.
The problem seems to be that I am appen开发者_如何学Pythonding data to a table which already has existing data. Can someone please offer some suggestions for how I can work around this?
Thanks
Verify you haven't overlooked any unique indexes on your table. Save this procedure in a standard module and call it from the Immediate Window with the name of your destination table.
Public Sub InspectIndexes(ByVal pTable As String)
Dim db As DAO.Database
Dim i As Long
Dim j As Long
Dim strFields As String
Set db = CurrentDb
With db.TableDefs(pTable)
Debug.Print "Indexes.Count = "; .Indexes.Count
For i = 0 To (.Indexes.Count - 1)
With .Indexes(i)
Debug.Print i + 1 & ": Index Name = "; .name
If .Primary Then
Debug.Print vbTab & "Primary Key (Unique)"
Else
Debug.Print vbTab & "Unique: "; .Unique
End If
Debug.Print vbTab & "Fields.Count = "; .Fields.Count
strFields = vbNullString
For j = 0 To (.Fields.Count - 1)
strFields = strFields & "; " & .Fields(j).name
Next j
strFields = Mid(strFields, 3)
Debug.Print vbTab & "Fields: "; strFields
End With
Next i
End With
Set db = Nothing
End Sub
Here is sample output where tblFoo has 3 indexes: primary key (unique by definition) on id; a unique index on num_field1 and num_field2; and a non-unique index on parent_id.
InspectIndexes "tblfoo"
Indexes.Count = 3
1: Index Name = both_num_fields
Unique: True
Fields.Count = 2
Fields: num_field1; num_field2
2: Index Name = parent_id
Unique: False
Fields.Count = 1
Fields: parent_id
3: Index Name = pkey
Primary Key (Unique)
Fields.Count = 1
Fields: id
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