C#: Properties Map

Is there a PropertiesMap in C# which exposes methods like GetDouble(string), GetDateTime(string), etc..?

IDictionary<string,string> f开发者_如何学JAVAorces users to take care of type conversion.

Yes there is ExpandoObject and it has a very clean syntax.

dynamic propertyMap = new ExpandoObject();
var item = propertyMap as IDictionary<String, object>;

item["A"] = DateTime.Now;
item["B"] = "New val 2";
propertyMap.C = 1234

Console.WriteLine(propertyMap.A);
Console.WriteLine(propertyMap.B);    
Console.WriteLine(propertyMap.C);

You can use the Dictionary class and add extension methods for all data types that you wanr to have Get method, or add a generic Get method and use it:

public static class Extensions
{
    public static T Get<T>(this Dictionary<string, object> dictionary, string key)
    {
        if (dictionary == null)
        {
            throw new ArgumentNullException("dictionary");
        }

        if (key == null)
        {
            throw new ArgumentNullException("key");
        }

        return (T)dictionary[key];
    }
}

You even can create alias for the Dictionary<string, object> type:

using PropertiesMap = System.Collections.Generic.Dictionary<string, object>;

And usage of this:

PropertiesMap pm = new PropertiesMap { { "1", 1 }, { "2", DateTime.Now }};
Console.WriteLine(pm.Get<int>("1"));
Console.WriteLine(pm.Get<DateTime>("2"));

You can use Convert, it can handle a lot of the conversions you will need.

Convert.ToDateTime(string value) //about 7 overloads
Convert.ToInt32(string value)
Convert.ToDouble(string value)

It has a lot of options for conversions, with plenty of overloads.

Can you use Convert.ToXXX? Not sure what your question has to do with IDictionary<string, string> though...

See this MSDN page.

A Dictionary<string,object> can store anything without conversion. However you will have to cast when retrieving the values:

var dict = new Dictionary<string,object>();
dict.Add("Name", "John");
dict.Add("Age", 20);
...
string name = (string)dict["Name"];
int age = (int)dict["Age"];