开发者

Why do they want an 'unsigned char*' and not just a normal string or 'char*'

EDIT: After taking adivce I have rearranged the parameters & types. But the application crashes when I call the digest() function now? Any ideas whats going wrong?

const std::string message = "to be encrypted";
unsigned char* hashMessage;

SHA256::getInstance()->digest( message, hashMessage ); // crash occurs here, what am I doing wrong?
printf("AFTER: n"); //, hashMessage); // line never reached

I am using an open source implementation of the SHA256 algorithm in C++. My problem is understanding how to pass a unsigned char* version of my string so it can be hashed?

This is the function that开发者_StackOverflow社区 takes a unsigned char* version of my string:

void SHA256::digest(const std::string &buf, unsigned char *dig) {
    init();
    update(reinterpret_cast<const unsigned char *>(buf.c_str()), static_cast<unsigned int>(buf.length()));
    final();
    digest(dig);
}

How can I convert my string(which I want hashed) to an unsigned char*?

The following code I have made causes a runtime error when I go to print out the string contents:

const std::string hashOutput;
char message[] = "to be encrypted";

printf("BEFORE: %s bb\n", hashOutput.c_str());
SHA256::getInstance()->digest( hashOutput, reinterpret_cast<unsigned char *>(message) );
printf("AFTER: %s\n", hashOutput.c_str()); // CRASH occurs here

PS: I have been looking at many implementations of SHA256 & they all take an unsigned char* as the message to be hashed. Why do they do that? Why not a char* or a string instead?


You have the parameters around the wrong way. Buf is the input (data to be hashed) and dig is the output digest ( the hash).

Furthermore, a hash is binary data. You will have to convert said binary data into some string representation prior to printing it to screen. Normally, people choose to use a hexadecimal string for this.


The reason that unsigned char is used is that it has guaranteed behaviours under bitwise operations, shifts, and overflow.

char, (when it corresponds to signed char) does not give any of these guarantees, and so is far less useable for operations intended to act directly on the underlying bits in a string.


The answer to the question: "why does it crash?" is "you got lucky!". Your code has undefined behaviour. In short, you are writing through a pointer hashMessage that has never been initialised to point to any memory. A short investigation of the source code for the library that you are using reveals that it requires the digest pointer to point to a block of valid memory that is at least SHA256_DIGEST_SIZE chars long.

To fix this problem, all that you need to do is to make sure that the pointer that you pass in as the digest argument (hashMessage) is properly initialised, and points to a block of memory of sufficient size. In code:

const std::string message("to be encrypted");
unsigned char hashMessage[SHA256_DIGEST_SIZE];

SHA256::getInstance()->digest( message, hashMessage );

//hashMessage should now contain the hash of message.


I don't know how a SHA256 hash is produced but maybe it involves some sort of arithmetic that needs to be done on a unsigned data type.

Why does it matter? Get a char* from your string object by calling the c_str() method then cast to unsigned char*.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜