mysql: exact match?
I'm pulling some data from mysql and counting occurrences of matches (seemingly equivalent to WHERE foo='bar'
). However, as I loop thru the data in PHP, my count is much lower than the count in mysql.
MYSQL> SELECT COUNT(foo) FROM database.table WHERE foo='bar';
# PHP
while ($response = mysql_fetch_assoc($surveydata)){
if ($response==='bar') {
$bar++;
}
}
The data might contain one or more &
, so I want to match only bar
and not bar & foobar
. I suspect mysql is counting bar
and bar & foobar
whereas php is only counting bar
and not bar & foobar
. Php is returning 1210
, and mysql is returning 1783
, so it's exactly practical to manually count to see who is right…
I googled around, but was surprised nothing relevant came up for "mysql exact match" or "mysql exactly equal" x,x
EDIT
here's the actual sql
SELECT COUNT(`race`) FROM `database`.`table` WHERE `completion status`='complete';
and the actual php
mysql_query("SELECT `race`,`etcetera` FROM `database`.`table` WHERE `completion status`='complete';");
$demographics=array(
"race"=>array(
"White"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Black"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Hispanic"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Asian"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Pacific Islander"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Multiracial"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Other"=>array('consented'=>0,'partial'=>0,'completed'=>0)
)
//more
);
while ($dbrecord = mysql_fetch_assoc($surveydata)) {
foreach ( $dbrecord as $dbfield=>$dbcellval ) {
foreach ( $demographics as $demographic=>&$options ) {
foreach ( $options as $option=>&$counter ) {
if ( $option==="Multiracial" && strpos($dbcellval,'&') >0 && strpos($dbcellval,'&')!==false ) {
if ($dbrecord['consent']==="1"){
$demographics["race"]["Multiracial"]['consented']++;
if ($dbrecord['completion status']==="partial") {
$demographics["race"]["Multiracial"]['partial']++;
} // if
else if ($dbrecord['completion status']==="complete") {
$demographics["race"]["Multiracial"]['completed']++;
} // else if
} // if
}
else if ($option===$dbcellval){
if ($dbrecord['consent']==="1"){
$counter['consented']++;
if ($dbrecord['completion status']==="partial") {
$counter['partial']++;
} // if
else if ($dbrecord['completion status']==="complete") {
$counter['completed']++;
} // else if
} // if
} // else if $option==$item
} // foreach $options
} // foreach $demographics
} // foreach $dbrec开发者_运维百科ord
} // while
the data from SELECT race FROM database.table
looks like:
White & Black
White
White & Asian
White & Asian & Black
Asian
Asian & Black
// etc
You can do this:
MYSQL> SELECT COUNT(foo) FROM database.table WHERE BINARY foo='bar';
BINARY does the magic!!!
If you want to count the records where foo
is exactly bar
, your SQL query is correct.
There's something wrong with your PHP code and the code you posted shouldn't work at all (should count 0 records).
MYSQL> SELECT COUNT(foo) AS rows FROM database.table WHERE foo='bar';
$response = mysql_fetch_assoc($surveydata);
echo $response['rows'];
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